A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 4 years ago

calculate ratio of distance travelled by body in 2nd and 4th second during free fall

  • This Question is Closed
  1. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    s= -half g * t^2..! now take ration of s1 and s2 and its equal to ratio of squares of the time intervals!

  2. unicorn
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    attachement below

    1 Attachment
  3. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    distance travelled in 4th second=1/2 *g*(16-9)=7/2*g distance travelled in 2nd second=1/2*g*(4-1)=3/2*g ratio=3/7

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.