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LollyLau
 4 years ago
[Warmup for previous challenge] Mark only has $1 coins and $2 coins in his wallet (poor guy). He has 10 coins and the total calue of the coins is $16. Find the number of $1 and $2 coins.
LollyLau
 4 years ago
[Warmup for previous challenge] Mark only has $1 coins and $2 coins in his wallet (poor guy). He has 10 coins and the total calue of the coins is $16. Find the number of $1 and $2 coins.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Let the number of $1 coins be x. Number of $2 coins = 10  x. x + 2(10  x) = 16 x + 20  2x = 16 x = 4 x = 4 10  x = 6

CornzyBlack
 4 years ago
Best ResponseYou've already chosen the best response.0hope u understand this the total sum of coins in mark's wallet is 10. But in mark's wallet he has an unknown number of $1 and 2$ coins. And the sum of the total coins in his wallet is $16. So lets take the unknown number of 1$ as x. And the unknown number of 2$ as y. Since the total number of coins in his wallet is 10 hence the sum of the unknown number of coins is also 10 that is, x+y = 10  equation. 1 So then the total value of coins is for simplicity sake i removed the $ sign x(1) + (2)y = 16.  equation 2 if x + y = 10 then, x = 10  y  equation 3 so substitute in equation 2, (10  y) 1 + 2 (y) = 16 10 y + 2 = 16 12  y = 16 y = 16  12 y = 4 from eqn 1 x + y = 10 substitute the value for x x + 4 = 10 x = 6 so mark has six 2$ coins and four 1$
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