You have 8 objects of similar size, but one object weighs a little bit more than the others. Given a balance scale, you must find out which object it is, but you may only use the scale twice.
What do you do?

- anonymous

- chestercat

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- 2bornot2b

If you allow me thrice, then I have the answer

- anonymous

Great; they say it can actually be done with only 2 "weighing" steps but still, I wanna see your answer!

- 2bornot2b

Just divide the 8 things into two groups, and place it in each of the pans of your balance.

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## More answers

- 2bornot2b

*of course two equal groups of 4

- 2bornot2b

So now you know when 4 contains the heavier one

- 2bornot2b

Divide that group into 2 groups each of 2,

- 2bornot2b

Now you know which two contains the heavier one

- anonymous

how about 3 and 3 for the first weighing?

- 2bornot2b

Now again place them, and you know the culprit

- anonymous

@satellite
Great; what's the rest

- anonymous

then if they are equal it is one of the other two, one weighing does it

- anonymous

and if it is one of the groups of 3, then weight two out of the three: if they are equal then it is the third

- 2bornot2b

satellite73 solved it

- anonymous

i think that does it

- anonymous

Very cool!

- anonymous

here is a question, that i can do but always have to start fresh because i always forget.
how do i multiply two 2 digit numbers with only 3 multiplications?
example
24
x 53

- anonymous

i am guessing adg knows because it is related to computer algorithms.

- 2bornot2b

Now solve this:
There are 10 cigarette packets, each containing 10 cigarettes. One of the packets contain cigarettes which are a bit heavier than the cigarettes in any of the other packets. Although each cigarette in anyone packet weighs the same.
Now with just one weighing you need to find out the culprit box.

- anonymous

i have seen this one before so i keep quiet

- 2bornot2b

great satellite73!

- anonymous

just select cigarettes from each box and compare!

- 2bornot2b

You are allowed to weight only once

- 2bornot2b

However, I must mention, you are allowed to use standardized weights

- anonymous

right
empty one box, leaving 1 cigarette in, and stuff that box with cigarettes from other boxes. and then..... I'm stuck :(

- 2bornot2b

Oh! Just don't try it that way. Keep it with you for a few days, then come back. You will surely have solved it by then

- anonymous

lol

- anonymous

alright... just look at the boxes and compare the weights...

- anonymous

ok i remember now. you can multiply 53 times 24 with 3 multiplications instead of 4

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