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anonymous
 4 years ago
You have 8 objects of similar size, but one object weighs a little bit more than the others. Given a balance scale, you must find out which object it is, but you may only use the scale twice.
What do you do?
anonymous
 4 years ago
You have 8 objects of similar size, but one object weighs a little bit more than the others. Given a balance scale, you must find out which object it is, but you may only use the scale twice. What do you do?

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2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1If you allow me thrice, then I have the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Great; they say it can actually be done with only 2 "weighing" steps but still, I wanna see your answer!

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1Just divide the 8 things into two groups, and place it in each of the pans of your balance.

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1*of course two equal groups of 4

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1So now you know when 4 contains the heavier one

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1Divide that group into 2 groups each of 2,

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1Now you know which two contains the heavier one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how about 3 and 3 for the first weighing?

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1Now again place them, and you know the culprit

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@satellite Great; what's the rest

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then if they are equal it is one of the other two, one weighing does it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and if it is one of the groups of 3, then weight two out of the three: if they are equal then it is the third

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1satellite73 solved it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0here is a question, that i can do but always have to start fresh because i always forget. how do i multiply two 2 digit numbers with only 3 multiplications? example 24 x 53

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am guessing adg knows because it is related to computer algorithms.

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1Now solve this: There are 10 cigarette packets, each containing 10 cigarettes. One of the packets contain cigarettes which are a bit heavier than the cigarettes in any of the other packets. Although each cigarette in anyone packet weighs the same. Now with just one weighing you need to find out the culprit box.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have seen this one before so i keep quiet

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just select cigarettes from each box and compare!

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1You are allowed to weight only once

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1However, I must mention, you are allowed to use standardized weights

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0right empty one box, leaving 1 cigarette in, and stuff that box with cigarettes from other boxes. and then..... I'm stuck :(

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1Oh! Just don't try it that way. Keep it with you for a few days, then come back. You will surely have solved it by then

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alright... just look at the boxes and compare the weights...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i remember now. you can multiply 53 times 24 with 3 multiplications instead of 4
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