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satellite73
 5 years ago
Multiply
\[24\times 53\] (or any two 2digit numbers) using 3 multiplications instead of the usual 4
satellite73
 5 years ago
Multiply \[24\times 53\] (or any two 2digit numbers) using 3 multiplications instead of the usual 4

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no takers on this one?

saifoo.khan
 5 years ago
Best ResponseYou've already chosen the best response.0No Takers, Only Under Takers!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think this is a computer algorithm problem. cuts down on multiplications

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.1I can do it using only two multiplications: 20 x 53 plus 4 times 53 oh  ok  misunderstood the question...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah that is still 4 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use ethiopian multiplication!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, what might that be?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0rosettacode.org/wiki/Ethiopian_multiplication

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow! not exactly what i had in mind though...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0method i had was somewhat shorter

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.1here is a list of algorithms for doing multiplication: http://en.wikipedia.org/wiki/Multiplication_algorithm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0funny i looked here and didn't see it

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.1One of these is particularly interesting: http://en.wikipedia.org/wiki/Karatsuba_algorithm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hint is \[(a+b)(c+d)=ac+ad+bc+bd\] and you need the numbers \[ac, bd, ad+bc\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah that is it! for example \[53\times 24\] \[5\times 2=10,3\times 4=12,(5+3)(2+4)=8\times 6=48, 481012=26\] 1 2 26 10 __________ 1 2 7 2

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.1yes  until you brought this up I was wasn't even aware of efficient multiplication methods. thanks for opening the door to new knowledge. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i never knew the name, and only remember it from a discrete algorithms class. in fact it is all i recall from that class

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0karatsuba! i will try to remember that name

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.1how can we ever forget a name like that! :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0especially with a bookmark!

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.1I have just invented a way for me to remember this: rabbits hop around and multiply very fast. so what is their favourite meal? "carrot soup" of course! (hence katatsuba)
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