## anonymous 5 years ago Solve for T: Equation below.

1. anonymous

$\sum_{j=0}^{4}\sin(k(xcos(\frac{2\pi j}{5})+ysin(\frac{2\pi j}{5}))-\omega T) = \sum_{j=0}^{4}\sin(k(xcos(\frac{2\pi j}{5})+ysin(\frac{2\pi j}{5})))$

2. anonymous

just realised that that isnt very visible. the other half of that equality is:$\sum_{j=0}^{4}\sin(k(x\cos(\frac{2\pi j}{5})+y\sin(\frac{2 \pi j}{5})))$

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