anonymous
  • anonymous
h(t)=cot t intervals: pie/4, 3pie/4 totally lost on this one... cant find a formula to plug in the intervals. Help :/ Thanks.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
are you supposed to graph?
anonymous
  • anonymous
\[\cot t = 1/\tan t\] So, cotangent is just an inverse of tangent. Hope this helps.
anonymous
  • anonymous
not "inverse" but "reciprocal"

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anonymous
  • anonymous
:-) Can be. I am not so sure about the terminology.
anonymous
  • anonymous
with functions "inverse" means "inverse function" so the inverse of \[f(x)=x+1\] is \[f^{-1}(x)=x-1\] not \[\frac{1}{x-1}\] which is the reciprocal
anonymous
  • anonymous
no, no graphing I just have to plug the intervals in and come up with the answer. answer in the book is, -4/pie how do I denote pie on this site?
anonymous
  • anonymous
\[h(t)=\cot t\] itervals given, \[\pi/4, 3\pi/4\]

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