## anonymous 4 years ago h(t)=cot t intervals: pie/4, 3pie/4 totally lost on this one... cant find a formula to plug in the intervals. Help :/ Thanks.

1. anonymous

are you supposed to graph?

2. anonymous

$\cot t = 1/\tan t$ So, cotangent is just an inverse of tangent. Hope this helps.

3. anonymous

not "inverse" but "reciprocal"

4. anonymous

:-) Can be. I am not so sure about the terminology.

5. anonymous

with functions "inverse" means "inverse function" so the inverse of $f(x)=x+1$ is $f^{-1}(x)=x-1$ not $\frac{1}{x-1}$ which is the reciprocal

6. anonymous

no, no graphing I just have to plug the intervals in and come up with the answer. answer in the book is, -4/pie how do I denote pie on this site?

7. anonymous

$h(t)=\cot t$ itervals given, $\pi/4, 3\pi/4$