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anonymous

  • 4 years ago

help me!!

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  1. anonymous
    • 4 years ago
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    with?

  2. anonymous
    • 4 years ago
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    solve the inequality (9/x+1)>9

  3. anonymous
    • 4 years ago
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    0<x<9/8

  4. anonymous
    • 4 years ago
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    thats not one of answer choices

  5. Hero
    • 4 years ago
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    ale5, you have not posted the equation correctly. There are two ways to interpret what you have posted.

  6. Hero
    • 4 years ago
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    I'll show you what i mean.

  7. Hero
    • 4 years ago
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    With the way you have posted it one person could interpret it as: |dw:1327171939658:dw| Another person could interpret it as: |dw:1327171974536:dw| Do you see the potential confusion here?

  8. anonymous
    • 4 years ago
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    oh okay good. I was like it should be that I did it twice

  9. Hero
    • 4 years ago
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    cinar, you approach produces no solution

  10. anonymous
    • 4 years ago
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    sorry if question is 9/(x+1)=9 then solution is -1<x<0

  11. Hero
    • 4 years ago
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    That isn't the question.

  12. Hero
    • 4 years ago
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    x = 1/63 is a solution so the actual solution appears to include fractions close to 0

  13. anonymous
    • 4 years ago
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    \[\frac9{x+1}>9\] \[\frac9{x+1}-9>0\] \[\frac{9-9x-9}{x+1}>0\] \[\frac{-9x}{x+1}>0\] \[\frac x{x+1}<0\]

  14. anonymous
    • 4 years ago
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    |dw:1327184116416:dw|

  15. Hero
    • 4 years ago
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    I don't believe that is the solution. 1/63 > 0

  16. anonymous
    • 4 years ago
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    \[\frac9x+1>9\] \[\frac9x>8\] \[\frac{9-8x}{x}>0\]

  17. anonymous
    • 4 years ago
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    |dw:1327184323364:dw|

  18. Mertsj
    • 4 years ago
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    have you guys noticed that you are a lot more interested in this problem than the asker is? He/she has disappeared.

  19. Hero
    • 4 years ago
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    I don't really pay attention to whether or not the original poster is here. I just care if the correct solution is presented.

  20. anonymous
    • 4 years ago
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    cinar I already answered it with that but its not it according to the asker. and they probably just guessed.

  21. anonymous
    • 4 years ago
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    I solved question either way..

  22. anonymous
    • 4 years ago
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    0<x<9/8

  23. Mertsj
    • 4 years ago
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    Divide both sides by 9 and get that the reciprocal of x+1 >1. The only way that the reciprocal of a number is greater than 1 is if the number is <1 and >0 So 0<x+1<1 -1<x<0

  24. Mertsj
    • 4 years ago
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    Another approach is to take the 2 cases Case 1 x+1>0 implies x>-1 and 9>9x+9 so 0>x Therefore -1<x<0 Case 2 x+1<0 implies x<-1 and 9<9x+9 so 0<x However x cannot be <-1 and >0 so this yields no solutions and Case 1 yields the only solutions.

  25. anonymous
    • 4 years ago
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    x<9/8

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spraguer (Moderator)
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