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anonymous
 4 years ago
help me!!
anonymous
 4 years ago
help me!!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0solve the inequality (9/x+1)>9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats not one of answer choices

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0ale5, you have not posted the equation correctly. There are two ways to interpret what you have posted.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I'll show you what i mean.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0With the way you have posted it one person could interpret it as: dw:1327171939658:dw Another person could interpret it as: dw:1327171974536:dw Do you see the potential confusion here?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay good. I was like it should be that I did it twice

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0cinar, you approach produces no solution

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry if question is 9/(x+1)=9 then solution is 1<x<0

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0x = 1/63 is a solution so the actual solution appears to include fractions close to 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac9{x+1}>9\] \[\frac9{x+1}9>0\] \[\frac{99x9}{x+1}>0\] \[\frac{9x}{x+1}>0\] \[\frac x{x+1}<0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327184116416:dw

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I don't believe that is the solution. 1/63 > 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac9x+1>9\] \[\frac9x>8\] \[\frac{98x}{x}>0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327184323364:dw

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0have you guys noticed that you are a lot more interested in this problem than the asker is? He/she has disappeared.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I don't really pay attention to whether or not the original poster is here. I just care if the correct solution is presented.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cinar I already answered it with that but its not it according to the asker. and they probably just guessed.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I solved question either way..

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Divide both sides by 9 and get that the reciprocal of x+1 >1. The only way that the reciprocal of a number is greater than 1 is if the number is <1 and >0 So 0<x+1<1 1<x<0

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Another approach is to take the 2 cases Case 1 x+1>0 implies x>1 and 9>9x+9 so 0>x Therefore 1<x<0 Case 2 x+1<0 implies x<1 and 9<9x+9 so 0<x However x cannot be <1 and >0 so this yields no solutions and Case 1 yields the only solutions.
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