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anonymous
 5 years ago
I have question in substation rule
anonymous
 5 years ago
I have question in substation rule

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1all those are z's right?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1did you let u=the bottom

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1\[u=e^z +z => du=(e^z+1 ) dz\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep i did in that way

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{e^0+0}^{e^1+1}\frac{du}{u}\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1\[\lnu_1^{e^1+1}\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1\[\lne^1+1\ln1=\ln(e+1)0=\ln(e+1)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah that is the right answer Thank you so much :)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1Do you understand all the steps I took?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i didn't understand one part of it which is the one before last step of it

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1you mean when I plugged in the upper limit and then minus plugged in the lower limit?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah why did you put e to 1 + 1 and e to 0 +0?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1so before the substitution the limits were 0<z<1 we wanted everything in terms of u after we made substitution if u=e^z+z, then e^0+0<z<e^1+1  if z=0, then u=e^0+0 if z=1, then u=e^1+1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh I see Thank you so much that was very helpful :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I understood each step that you had done
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