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anonymous
 5 years ago
How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas?
Unbalanced equation: C2H6 + O2 → CO2 + H2O
anonymous
 5 years ago
How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas? Unbalanced equation: C2H6 + O2 → CO2 + H2O

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0balenced equation is C2H6+5O2 yield 2CO2+3H2O

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the balanced equation is 2(C2H6) + 7(O2) >>>> 4(CO2)+6(H2O)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you do the stoichiometry you get an answer of 0.556 mol of ethane (C2H6)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(62.3gO2) * (1mol O2 / 31.998 g O2) * (2mol C2H6 / 7mol O2) = 0.566 mol ethane

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0with sig figs > .389 mol C2H6 \[62.3g \space O_{2} \times 1mol O_{2} \times 4molC_{2} H_{6} \over 32.00g \space O_{2} \times 7mol \space O_{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@tktechie where did you get the 4 mol of C2H6 in your stoichiometry?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@ SalvatoreTRM Oh crud! That was a typo.. and the answer i gave was wrong, too. the answer was based off of the original balace that the asker gave. I didn't think to check it.
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