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anonymous
 4 years ago
A dehydrated patient needs a 7.9% saline IV. Unfortunately, the hospital only has bags of 3% and 10% saline solutions. How many liters of each of these solutions should be mixed together to yield 3 liters of the desired concentration?
anonymous
 4 years ago
A dehydrated patient needs a 7.9% saline IV. Unfortunately, the hospital only has bags of 3% and 10% saline solutions. How many liters of each of these solutions should be mixed together to yield 3 liters of the desired concentration?

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Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0x liters of 3% 3x liters of 10$ .03x + .10(3x)= .079(3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok do I solve for x and y? to get the concentrations from the 3& and the 10% bags?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.030x+100(3x)=237 30x+300100x=237 70x=63 x=.9 liters of 3% solution 3x = 2.1 liters of 10 % solution

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0First multiply by 1000 to get rid of the decimals.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so that will be concentration from the 3% bag right? then I need to find the concentration from the 10% bag correct?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Good!! That is the amount of 3% solution that is needed.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0my approach works, I just make mistakes

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0x + y = 3 .03x + .1y = .079(3)
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