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anonymous

  • 5 years ago

 A dehydrated patient needs a 7.9% saline IV. Unfortunately, the hospital only has bags of 3% and 10% saline solutions. How many liters of each of these solutions should be mixed together to yield 3 liters of the desired concentration?

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  1. Mertsj
    • 5 years ago
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    x liters of 3% 3-x liters of 10$ .03x + .10(3-x)= .079(3)

  2. anonymous
    • 5 years ago
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    ok do I solve for x and y? to get the concentrations from the 3& and the 10% bags?

  3. Mertsj
    • 5 years ago
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    30x+100(3-x)=237 30x+300-100x=237 -70x=-63 x=.9 liters of 3% solution 3-x = 2.1 liters of 10 % solution

  4. Mertsj
    • 5 years ago
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    First multiply by 1000 to get rid of the decimals.

  5. anonymous
    • 5 years ago
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    ok , I got x = 0.9

  6. anonymous
    • 5 years ago
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    so that will be concentration from the 3% bag right? then I need to find the concentration from the 10% bag correct?

  7. Mertsj
    • 5 years ago
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    Good!! That is the amount of 3% solution that is needed.

  8. Mertsj
    • 5 years ago
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    Exactly

  9. anonymous
    • 5 years ago
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    ok ty

  10. Mertsj
    • 5 years ago
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    yw

  11. Hero
    • 5 years ago
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    my approach works, I just make mistakes

  12. Hero
    • 5 years ago
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    x + y = 3 .03x + .1y = .079(3)

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