anonymous
  • anonymous
The percentage of automobile cunsumers who are under 50 years of age degreased linerly from 55.9% in 1990 to 52.4% in 2005. Predeict when the percentage will be 48%?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Hero
  • Hero
Just use the slope formula to get the slope, then use the point slope formula to find the equation
anonymous
  • anonymous
So, \[52.4-55.9/105-90\]?
Hero
  • Hero
yes, that's a good start.

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anonymous
  • anonymous
Well somewhere I'm getting hung up...so i end up with -3.5/15. Then go \[55.9=-3.5/15(90)+b? \]
anonymous
  • anonymous
if this is right, that's where I'm stuck. I now have to predict when it will be 48%? Plug 48 into y? Solve
Hero
  • Hero
Wait a sec...
anonymous
  • anonymous
K :S
Hero
  • Hero
Sorry, I thought you were using the point slope form. You decided to do this the other way... What do you get for b?
anonymous
  • anonymous
Well originally 76.9
Hero
  • Hero
That's correct
Hero
  • Hero
So what is your y = mx + b formula now?
anonymous
  • anonymous
Should i plug the 48 in as y?
Hero
  • Hero
yes
anonymous
  • anonymous
\[48=-3.5/15x+76.9\] Solve for x
Hero
  • Hero
yes,and what do you get for x?
anonymous
  • anonymous
-26.57?
Hero
  • Hero
I get year 2023 and 10.2/12 months
anonymous
  • anonymous
Hmm...so first I -76.9 from both sides?
Hero
  • Hero
so right around October of year 2023
Hero
  • Hero
Yes correct
anonymous
  • anonymous
End up with -28.9 = -3.5/15x
Hero
  • Hero
yes
anonymous
  • anonymous
Do I convert m to -2.33?
Hero
  • Hero
wait a sec...
Hero
  • Hero
You should just solve it without converting.
anonymous
  • anonymous
So did you get 433.5/3.5?
anonymous
  • anonymous
123.86
anonymous
  • anonymous
So in years 1900 + 123.6 = 2023.6? That seems a lot close to what you had
Hero
  • Hero
Close enough. Good job
anonymous
  • anonymous
Wow...what a pain. OK, well thank you for the time. That is a lot closer to a realistic answer. Just need to make sure I follow each step carefully. Thanks again.

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