## anonymous 5 years ago Simplify:n squared + 8n + 16 over n squared minus 6n + 9 divided by n + 4 over n minus 3

1. anonymous

$\frac{n^2+8n+16}{n^2-6n+9}\times \frac{n-3}{n+4}$ is a start, then factor as $\frac{(n+4)(n+4)(n-3)}{(n-3)(n-3)(n+4)}$ and so some canceling

2. jhonyy9

(n+4)(n+4) ----------- (n-3)(n-3)

3. jhonyy9

so this divided by (n+4)/(n-3)

4. jhonyy9

so will get (n+4)/(n-3)

5. anonymous

Thanks! :)

6. jhonyy9

yw good luck bye