anonymous
  • anonymous
Solve x2 + 4x – 12 = 0 by completing the square. Please help!
Mathematics
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anonymous
  • anonymous
Solve x2 + 4x – 12 = 0 by completing the square. Please help!
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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myininaya
  • myininaya
\[x^2+4x=12\] added 12 on both sides
myininaya
  • myininaya
\[x^2+4x+4=12+4\] added 4 on both sides to complete the square on the left hand side
myininaya
  • myininaya
\[(x+2)^2=16\]

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myininaya
  • myininaya
Now take square root of both sides don't forget the plus or minus
myininaya
  • myininaya
\[x+2 = \pm \sqrt{16}\] \[x+2= \pm 4\]
myininaya
  • myininaya
Now subtract 2 on both sides \[x=-2 \pm 4\] this means we have two values for x \[x=-2+4 \text{ or } x=-2-4\]
myininaya
  • myininaya
\[x=2 \text{ or } x=-6\]
anonymous
  • anonymous
\[x ^{2}+4x+4-16=0 \rightarrow (x+2)^2=16 \rightarrow x+2= \pm 4;\]; x=2 and x=-6
Hero
  • Hero
x2 + 4x – 12 = 0 x^2+6x-2x-12 =0 x(x+6)-2(x+6) = 0 (x+6)(x-2) = 0 x = -6,2
anonymous
  • anonymous
thanks guys! (:

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