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- anonymous

Express the area of each figure as a monomial.
How would I solve
7x^4
if the formula is
s^2
Steps on how you got the answer are appreciated, it'll help me on my test. Thanks.

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- anonymous

- schrodinger

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- myininaya

are you saying we have a square and each side has length 7x^4?

- myininaya

if so
then you do
\[(7x^4)^2=7^2x^{4 \cdot 2}\]

- myininaya

\[=49x^8\]

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- anonymous

|dw:1327185937099:dw|

- anonymous

not sure if the fact that it's a circle and not a square would affect the outcome of the answer..

- anonymous

What do you mean by "each figure"? the circle?

- anonymous

Yes.

- anonymous

So, you want the area of the circle in terms of x?

- anonymous

Honestly, I have no idea what this question is asking me to do..
It just tells me to express the area of the figure as a monomial.

- myininaya

but the figure they give you is a circle right?

- myininaya

\[A=\pi r^2=\pi (7x^4)^2\]

- myininaya

area of a circle is pi times radius squared

- myininaya

the radius in the circle you drew above is 7x^4

- myininaya

so i replaced r with 7x^4

- anonymous

you beat me to it myin

- myininaya

\[A=\pi(7^2 \cdot x^{4 \cdot 2})\]
:)

- myininaya

\[A=49x^8 \pi\]

- myininaya

since 7^2=49 and x^(4 times 2)=x^8

- anonymous

Thank you :)

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