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anonymous

  • 5 years ago

Express the area of each figure as a monomial. How would I solve 7x^4 if the formula is s^2 Steps on how you got the answer are appreciated, it'll help me on my test. Thanks.

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  1. myininaya
    • 5 years ago
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    are you saying we have a square and each side has length 7x^4?

  2. myininaya
    • 5 years ago
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    if so then you do \[(7x^4)^2=7^2x^{4 \cdot 2}\]

  3. myininaya
    • 5 years ago
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    \[=49x^8\]

  4. anonymous
    • 5 years ago
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    |dw:1327185937099:dw|

  5. anonymous
    • 5 years ago
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    not sure if the fact that it's a circle and not a square would affect the outcome of the answer..

  6. anonymous
    • 5 years ago
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    What do you mean by "each figure"? the circle?

  7. anonymous
    • 5 years ago
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    Yes.

  8. anonymous
    • 5 years ago
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    So, you want the area of the circle in terms of x?

  9. anonymous
    • 5 years ago
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    Honestly, I have no idea what this question is asking me to do.. It just tells me to express the area of the figure as a monomial.

  10. myininaya
    • 5 years ago
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    but the figure they give you is a circle right?

  11. myininaya
    • 5 years ago
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    \[A=\pi r^2=\pi (7x^4)^2\]

  12. myininaya
    • 5 years ago
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    area of a circle is pi times radius squared

  13. myininaya
    • 5 years ago
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    the radius in the circle you drew above is 7x^4

  14. myininaya
    • 5 years ago
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    so i replaced r with 7x^4

  15. anonymous
    • 5 years ago
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    you beat me to it myin

  16. myininaya
    • 5 years ago
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    \[A=\pi(7^2 \cdot x^{4 \cdot 2})\] :)

  17. myininaya
    • 5 years ago
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    \[A=49x^8 \pi\]

  18. myininaya
    • 5 years ago
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    since 7^2=49 and x^(4 times 2)=x^8

  19. anonymous
    • 5 years ago
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    Thank you :)

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