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anonymous

  • 5 years ago

ln e ^ x + 4y

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  1. myininaya
    • 5 years ago
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    not sure what we are doing here

  2. anonymous
    • 5 years ago
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    what do you want done here. just simplified?

  3. anonymous
    • 5 years ago
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    yes

  4. anonymous
    • 5 years ago
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    and is the +4y inside of the ln

  5. anonymous
    • 5 years ago
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    the question was just simplify in and then it gave the equation

  6. anonymous
    • 5 years ago
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    yes but how was it written, was it\[\ln (e ^{x}+4y)\] or was it \[\ln (e ^{x})+4y\]

  7. anonymous
    • 5 years ago
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    1st one

  8. anonymous
    • 5 years ago
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    figure the second, i.e., x+4y

  9. anonymous
    • 5 years ago
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    non sense the first (simplify I say)

  10. anonymous
    • 5 years ago
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    okay then you distribute the ln to have \[\ln e ^{x} + \ln(4y)\] and the natural log of lne^x the ln and e cancel to just be x so \[x + \ln(4y)\]

  11. anonymous
    • 5 years ago
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    ok thanks

  12. TuringTest
    • 5 years ago
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    no you don't distrubite the natural log\[\log(a+b)\neq\log a+\log b\]if the problem is to simplify\[\ln(e^x+4y)\]it cannot be done

  13. myininaya
    • 5 years ago
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    turing is right

  14. anonymous
    • 5 years ago
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    oh sorry i was doing that two added natural logs added could be combined my mistake. and luis, the problem isnt written as you wrote it

  15. anonymous
    • 5 years ago
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    but if your telling the asker to look at your answer, if your answer isnt answering the problem he is asking why would he/she look at it? thats the whole point? the point is that you are answering the wrong question? i wont get that because it doesnt make sense

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