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anonymous

  • 4 years ago

ABCD is a rectangle with AD=10. If the shaded area is 100 units2, then what is the shortest distance between the two semicircle?

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  1. anonymous
    • 4 years ago
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    |dw:1327187342839:dw|

  2. Mertsj
    • 4 years ago
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    If AD = 10, the radius of the semicircle is 5 and the area of the entire circle is 25pi. So the area of the rectangle must be 100 + 25 pi and so the length of the rectangle is the area divided by the width which is given to be 10. So the length is 10+2.5 pi. Now if we subtract 10 (the radius of each semicircle) from that, we have 2.5 pi as the shortest distance between the two semicircles.

  3. anonymous
    • 4 years ago
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    Thank you!

  4. Mertsj
    • 4 years ago
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    yw

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