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anonymous
 4 years ago
dy/dx=(1+2x^2)/(x cos y)
anonymous
 4 years ago
dy/dx=(1+2x^2)/(x cos y)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Find the general solution to the following differential equation :

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=dy%2Fdx%3D%281%2B2x%5E2%29%2F%28x+cos+y%29

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\cos(y) dy=\frac{1+2x^2}{x} dx\] integrate both sides

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{}^{}\cos(y) dy=\int\limits_{}^{}(\frac{1}{x}+2x) dx\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\sin(y)=\lnx+x^2+C\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0∫ (1+2x^2)/(x cos y) dx=( X^2+log(x))sec(y)+c Is this correct myininaya ?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1we have to do separation of variables

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1we had \[\frac{dy}{dx}=\frac{1+2x^2}{x \cos(y)}\] I want to get my y's together and my x's together so first thing i did was multiply cos(y) on both sides \[\cos(y) \frac{dy}{dx}=\frac{1+2x^2}{x}\] Then I multiplied dx on both sides \[\cos(y) dy=\frac{1+2x^2}{x} dx\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1Now we can integrate both sides

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have to say thank you as well.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1Aww... you're welcome :)
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