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anonymous

  • 5 years ago

In the diagram, the circle is inscribed in the square. This means that the circle and the square share points S, T, U, and V, and the width of the square is exactly equal to the diameter pf the circle. What percentage of the line segment XY is outside the circle?

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  1. anonymous
    • 5 years ago
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    |dw:1327192015451:dw|

  2. dumbcow
    • 5 years ago
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    The diameter is 2r The length of the side of the square is also 2r XY = sqrt(2)*2r length outside circle = (sqrt(2)*2r - 2r) = 2r(sqrt(2) -1) percent outside circle = 2r(sqrt(2) -1) / sqrt(2)*2r = (sqrt2 -1)/sqrt2 = 0.29

  3. anonymous
    • 5 years ago
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    ok, Thank you!

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