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anonymous
 4 years ago
How many solutions exist for the system y = 2x + 5 and y = 0.2x  4?
A. no solution
B. one solution
C. infinitely many solutions
anonymous
 4 years ago
How many solutions exist for the system y = 2x + 5 and y = 0.2x  4? A. no solution B. one solution C. infinitely many solutions

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TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[y=2x+5\]\[y=0.2x4\]multiply the second equation by ten\[y=2x+5\]\[y=2x40\]add them together and see if you get a statement that is always true, never true, or a single answer. If it is always true, infinite solutions. If it is never true, no solutions. If it yields an answer, that is the 1 solution.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[10y=2x40\]supposed to be in las line

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If it is always true, infinite solutions. If it is never true, no solutions. If it yields an answer, that is the 1 solution. I don't understand :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think we have B. one solution in here.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It was rather an elementary approach :)

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1... you can try to figure it out is always my response. It may be enlightening\[\large y=2x+5\]\[\large 10y=2x40\]add 'em up.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You mean if it's an identity then no solutions right?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1:/ yeah, that makes perfect sense...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol, why that face? :)

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1Your sarcastic witicisms try to confound me. It almost works at times ;)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks for the help :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hehe, I can never to do that to you ;)
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