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anonymous
 4 years ago
Anyone know know how I can find the % of the piece I have cut (20.0 cm by 20.0 cm or 8 inch by 8 inch) in relation to the whole roll (area is 6.96 m^2)?
anonymous
 4 years ago
Anyone know know how I can find the % of the piece I have cut (20.0 cm by 20.0 cm or 8 inch by 8 inch) in relation to the whole roll (area is 6.96 m^2)?

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JFraser
 4 years ago
Best ResponseYou've already chosen the best response.2Find the area of the individual piece (in m2), divide by the total area. Percentage of the total area.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I need to find the cost PER ATOM of my sample aluminum foil (20.0 cm by 20.0 cm), which has a mass of 1.76 g. I found its number of moles: 0.0652 mol, and its number of atoms in the sample: 3.925 x 10^22. Is it good so far?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh.. so how do I find the total area of the sample? o.o

JFraser
 4 years ago
Best ResponseYou've already chosen the best response.2try length x width, in meters

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so basically convert 20.0 cm into metres, which is 0.2 m.

JFraser
 4 years ago
Best ResponseYou've already chosen the best response.2So the area of the sample is 0.4m^2, and the area of the whole roll is 6.96m^2. Not a very big percentage. Multiply that percentage by the cost per roll and you have the cost per sample

JFraser
 4 years ago
Best ResponseYou've already chosen the best response.2Divide the cost of the sample by the number of atoms, and you have the cost per atom.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0:O THANK YOU SO MUCH JFRASER!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So.. I got Area % = Area of sample/area of whole roll = 0.4 m^2/6.96 m^2 = 0.00574 m^2. Cost per sample = Area % x Cost per roll = 0.0575 m^2 x $1.59 = $ 0.0914/m^2, and cost per atom = Cost per sample/# of atoms = 0.0914 m^2/3.925 x 10^22 atom = 2.29299363 x 10^20... So the cost per atom is 2.29 x 10^22? o.O ahh!!

JFraser
 4 years ago
Best ResponseYou've already chosen the best response.2when you divide\[\frac{$0.0914}{3.925*10{^2}{^2}}\] you should gets some incredibly small #, not 10^20.If the whole roll only costs $1.59, a small fraction of that roll can't cost billions of times more money. You probably divided upside down.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh.. so wait is it going to be divided: $0.0914  3.925*10^22 = 2.29299363*10^24... I'm so confused D; I'm so sorry!

JFraser
 4 years ago
Best ResponseYou've already chosen the best response.2that's the cost per atom of the aluminum.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is? How? $2.29? o.o

JFraser
 4 years ago
Best ResponseYou've already chosen the best response.2don't ignore the exponent at the tail end of that number. it's not $2.29, it's $0.0000000000000000000000229

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh. is it really the cost? It looks weird for it to be cost.. o.o

JFraser
 4 years ago
Best ResponseYou've already chosen the best response.2that's the point. It's an incredibly small cost per atom, because you have an incredibly large number of atoms in the aluminum foil.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh.. so it's correct or wrong? D: ahh.
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