help, z(c+5)-8(5+c)

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help, z(c+5)-8(5+c)

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Distribute z zc + 5z Now distribute -8 -40 - 8c Giving us: zc + 5z - 40 - 8c
omg, i can't figure these out for the life for of me.
Ok, lets take this step by step.

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Other answers:

thanks.
Looking at the equation given, we have to use the distributive property. What can we distribute here?
z or -8
|dw:1327199125344:dw|
wait let absorb this?
z AND -8 When we distribute z to (c + 5) we get?
zc+5z
Right! Now lets distribute -8 to (5 + c)
And we get?
k. -40-8c
Now lets put it all together, to get?
(zc+5z)(-40-8)
oops (zc+5z)(-40-8c)
Dont forget, its ( -40 - 8c) Since that cannot be simplified further, that will cluded to be our answer.
*Conclude
ok i checked the book and the answer is (c+5)(z-8)
What were the directions to this problem? Because the way you wrote it, Baala and I cocnluded to t he same answer.
i know i got that also hold on.... it is factoring polynomials.
Haha, then this would be solved in a different more convulted way.
u understand it. by the way thanks for your help.
Well its quite easy actually. Your original question was: z ( c+ 5 ) - 8 (5 + c) You see how the expressions in the paranthesis are the same? They are both ( c + 5) right? Therefore, it creates one portion of this factorial polynomial. ( c + 5) Now you see the constants outside the paranthesis? Lets put those "together" to get z - 8 Correct? This creates another portion of the factorial polynomial. (z - 8) Put these both together and you get the answer to be: (z - 8 ) ( c+ 5)
Anytime sweetie =)
o. o. see that makes sense... lol
Haha ;)
omg, it has been 20+ yrs since i have dona any algebra... a bit rusty... lol
Well then you must be quite older than me! :P
Keep intact with Openstudy to revive the past lessons on Algebra
lol yeah i am up there... lol thanks sooooo much...
No problemo =D the pleasure is mine
z(c+5) - 8(5+c)= (z - 8) (5+c)

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