## emanramirez12 3 years ago solving square root equations: square root of x-1+3=x? help please

1. Caramel1031

Are you sure this is the equation? It's not possible for a number plus two to equal itself.

2. emanramirez12

$\sqrt{X-1 +3=x}$

3. emanramirez12

It's like that but with the 3 and the x out the square root

4. Caramel1031

In that case, first you want to isolate the square root, so subtract 3 from both sides$\sqrt{x-1}+3-3=x-3$ leaving you with $\sqrt{x-1}=x-3$ next, square both sides to get rid of the square root sign (remember, a square root is the same thing as taking something to the one-half power. Refer to your exponent rules if you're still confused).$\sqrt{x-1}^{2}=(x-3)^{2}$ now you have $x-1=(x-3)^{2}$ expand the right hand side of the equation using the foil method, and you get $x-1=x ^{2}-6x+9$ subtract x-1 from both sides, leaving the left side zero. Now you have $0=x ^{2}-7x+10$ Use the formula $x=(-b+or -\sqrt{b ^{2}-4ac})\div2a$ to get your answer.