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Caramel1031
 3 years ago
Best ResponseYou've already chosen the best response.0Are you sure this is the equation? It's not possible for a number plus two to equal itself.

emanramirez12
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{X1 +3=x}\]

emanramirez12
 3 years ago
Best ResponseYou've already chosen the best response.0It's like that but with the 3 and the x out the square root

Caramel1031
 3 years ago
Best ResponseYou've already chosen the best response.0In that case, first you want to isolate the square root, so subtract 3 from both sides\[\sqrt{x1}+33=x3\] leaving you with \[\sqrt{x1}=x3\] next, square both sides to get rid of the square root sign (remember, a square root is the same thing as taking something to the onehalf power. Refer to your exponent rules if you're still confused).\[\sqrt{x1}^{2}=(x3)^{2}\] now you have \[x1=(x3)^{2}\] expand the right hand side of the equation using the foil method, and you get \[x1=x ^{2}6x+9\] subtract x1 from both sides, leaving the left side zero. Now you have \[0=x ^{2}7x+10\] Use the formula \[x=(b+or \sqrt{b ^{2}4ac})\div2a\] to get your answer.
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