ok gang struggling w/ this one. it's factoring polynomials. 3y^(3)-12y^(2)+y-4

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ok gang struggling w/ this one. it's factoring polynomials. 3y^(3)-12y^(2)+y-4

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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ok i will hint you take 3y^2 common in the first two terms
k,
\[3y^2(y-4)+1(y-4)=0 \rightarrow(3y^2+1)(y-4)=0\]

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ok that 0 was a mistake
do u get it/?
sorry i am back. my dog had to be let out..
lol which breed of dog do u have (off topic)
white german shephard... she kept poking me w/ her nose... she must have really had to go, cuz she was making noises this last time..
ok so do u get this question?
yes... and thanks...
my pleasure :D

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