• anonymous
I think this question is pretty straightforward and I'm making it more complicated than it needs to be. Find the equation of the vertical plane perpendicular to the y-axis and through the point (2, 3, 4) I know the x-axis is perpendicular to the y-axis, and in 3D space I know this must be the XZ plane. From here, I get a little lost coming up with the equation. If the equation of a plane is a(x-x_0) + b(y-y_0) + c(z-z_0) = 0, then my a = 2, b = 3, c = 4. But I feel like that's not right. Do I plug in those values for x, y, z instead?
MIT 18.02 Multivariable Calculus, Fall 2007
• Stacey Warren - Expert brainly.com
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SOLVED
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