Can someone help me with matrices?

- anonymous

Can someone help me with matrices?

- Stacey Warren - Expert brainly.com

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- schrodinger

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- anonymous

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- Hero

no :P

- anonymous

Can you help me with Question #42

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## More answers

- anonymous

LOL

- anonymous

What are the steps?

- TuringTest

what's the difference between that and #41 ?
find the inverse then divide by the constant to get A
there are quite a few ways to find the inverse

- Hero

i would help you, but I don't know the steps.

- anonymous

Well I need to solve #42 LOL

- anonymous

To find the inverse I use the identity matrix

- anonymous

Ya hero I know :D

- Hero

How come you didn't just use tutor.com?

- anonymous

They dont know linear algebra

- Hero

Yes they do, you just went to the wrong person

- TuringTest

What did you get for the inverse of 4A ?

- anonymous

No thsy give you (4A)^-1

- anonymous

So I first divided by 1/4

- anonymous

and then I used the identity matrix thingy

- Hero

rld, how come you don't just read the book?

- TuringTest

no that is the last step!

- anonymous

LOL ok

- TuringTest

dividing by 4 is last

- anonymous

I knew I was doing it wrong

- anonymous

My book never told me what to do lol

- TuringTest

\[((4A)^{-1})^{-1}=4A\]then you can scalar divide by 4...

- anonymous

Hey i can help you.

- Akshay_Budhkar

am i allowed to help you?

- anonymous

LOL Thanks turing :D
How can u think while standing on ur head?

- anonymous

Guys turing beat u lOL

- TuringTest

Go ahead I though rld had it from here since he know the identity matrix trick...

- Akshay_Budhkar

Turing cheated !! he answered before us

- anonymous

Turing is amazing!

- Akshay_Budhkar

:P

- TuringTest

thought*

- TuringTest

lol

- anonymous

ya i know what to do from here lol

- Akshay_Budhkar

i didnt read the question (anyways i dont know matrices as good as him)

- anonymous

lol ya thanks guys :D

- Akshay_Budhkar

thanks for thanking me as well

- anonymous

I know a very fast method to find the inverse of 2X2 matrices.

- anonymous

ok shoot

- anonymous

Ideally it takes me about 5 seconds ;)

- TuringTest

http://tutorial.math.lamar.edu/Classes/LinAlg/FindingInverseMatrices.aspx
I'm guessing you're thinking theorem 4 on this page

- anonymous

Fool u will be able to help me I am not finished my work. I have another few hours of linear algebra. I am not going to bed for another few hours so like stick around LOL

- Akshay_Budhkar

ok so now u tell Fool to help.. cant i and turing help?

- anonymous

LOL the more the merrier

- anonymous

ya i know that shortcut

- anonymous

At least i know something

- Akshay_Budhkar

so y ou r telling me that... Akshay atleast i know something, not like you

- anonymous

Yep exactly that Turing :)

- anonymous

LOL No i feel stupid around u guys so like at least i know something

- razor99

the maths u do is very difficult

- Hero

rld, just post all your questions here so I can learn linear algebra before taking it

- anonymous

LOL Linear algebra is like easy once you get it. So like I only post one in like 15 questions

- Hero

By the way, on tutor.com a guy named Ewain G. is the smartest person on there. He will help you with anything math related no matter how difficult.

- razor99

gotta run guyz i have to got to the hospital

- anonymous

HUH????? @razor

- anonymous

In words the adjoint of a 2X2 matrix can be found by swapping the diagonal elements and changing the sign of the off-diagonals.

- anonymous

Alrighty fool

- Akshay_Budhkar

yea we were taught that in grade 12 @fool

- anonymous

lol I never learn that in grade 12

- anonymous

Wow great akshay I never passed my grade 12 :P

- Akshay_Budhkar

yea yea that is why u r in iit.. i passed that is why i am not in iit :P -_-

- razor99

A = 1.00 2.00
3.00 4.00
Determinant
det(A) = 1.00 2.00
3.00 4.00
= -2
The Inverse Matrix of A is:
A-1 = -2.00 1.00
1.50 -0.50

- anonymous

ok Thanks Guys (espeially turing) for ur help gotta go study otherwse wont get to sleep tonite

- anonymous

Yes, you are right Akshay, now you have established that IIT takes poor students like me :P

- anonymous

LOL @FOOL

- Akshay_Budhkar

LOL

- Akshay_Budhkar

especially turing? i helped u as well.. 1+1=2

- anonymous

idk fight it out with turing

- anonymous

Of-course she will thank Turing, he is one with pic ;)

- Akshay_Budhkar

LOLL

- anonymous

LOL no cuz he is upside down

- Akshay_Budhkar

ok i need to change my pic!! :P

- Akshay_Budhkar

turing is feeling shy?

- Akshay_Budhkar

why is he not asnwering?

- anonymous

LOL Turing isnt shy

- anonymous

lol not fair akshay stop hitting on her:P She clearly likes Turing not us :P

- Akshay_Budhkar

how do you know?

- Akshay_Budhkar

ok i accept the face fool that we are FOOLS turing isn't :P

- TuringTest

I am always sort of doing something else...
I just found what the person was missing in the problem is all

- anonymous

LOL Tuirng is very modest. turing they are just joking around. Dont even argue with them LOL

- Akshay_Budhkar

Turing is modest and we are jokers?

- razor99

are u stressed

- Akshay_Budhkar

just because he has a pic?

- anonymous

That's mean Rld :P

- anonymous

K guys gottta go. Otherwise i wont have time to spend with my

- Akshay_Budhkar

my..

- anonymous

family and friends

- Akshay_Budhkar

LOl

- anonymous

Turing :P

- Akshay_Budhkar

LOL

- anonymous

Guys u r crazy

- razor99

rld did u get your answre

- Akshay_Budhkar

jokers---> crazy

- anonymous

I seriously am not like that

- anonymous

No I am just a Fool ;)

- anonymous

Ask lana

- Akshay_Budhkar

i am following his footsteps :P

- Akshay_Budhkar

Lalaly

- anonymous

LOL Guys it was great chatting with u.

- Akshay_Budhkar

goodnight

- Akshay_Budhkar

Great ppl grat chats :D ;)

- anonymous

Bye I may be back :D

- razor99

what is the time in your country

- anonymous

And if I have time I will also do some calc

- Akshay_Budhkar

11:08 pm

- anonymous

razor I got my answer

- Akshay_Budhkar

calc!!!!!! i can help u in that :P

- razor99

good night

- anonymous

ya but i gotta go otherwise I wont be able to start BYE EVERYONE (INCLUDING ZARKON)

- razor99

our country almost 9 am

- anonymous

Bye :)

- Akshay_Budhkar

Zarkon is so quite

- Zarkon

yep

- pokemon23

Hero I'm scared

- Akshay_Budhkar

Zarkon!

- Akshay_Budhkar

i am so happy that u r talking :P

- Hero

Scared of what? The boogie man?

- pokemon23

no anonymous

- pokemon23

http://www.youtube.com/watch?v=N2WqU-HvyUI&feature=g-logo&context=G2d684acFOAAAAAAAXAA

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