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anonymous

  • 4 years ago

Vx is the velocity of a particle moving along the x-axis as shown. If x = 2.0 m at t = 1.0 s, what is the position of the particle at t = 6.0 s?

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  1. anonymous
    • 4 years ago
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    here is the graph

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  2. anonymous
    • 4 years ago
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    These are the answers they give me +2.0 m 6.0 m −1.0 m −2.0 m +1.0 m

  3. ash2326
    • 4 years ago
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    find the area under the curve it'll give the total displacement till t= 1 sec , the area under the curve is =(2-0)*1+1/2 (4-2)*(2-1)=3 units it's given the particle was on x=2 units at t=1 so so it was on x=-1 at the starting Let's find first the area of graph above x axis= 1/2 *(2-0)*(4-0)=4 units in +ve x -axis direction area below the x -axis = 1/2 (6-2)(-2-0)=-4 units so the total displacement will be -4+4=0 so it'll be at it's original position x=-1 option 3

  4. anonymous
    • 4 years ago
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    thanks a bunch it worked

  5. anonymous
    • 4 years ago
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    2+(5*vx)

  6. anonymous
    • 2 years ago
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    please could any one tell me why x=-1

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