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anonymous
 4 years ago
Vx is the velocity of a particle moving along the xaxis as shown. If x = 2.0 m at t = 1.0 s,
what is the position of the particle at t = 6.0 s?
anonymous
 4 years ago
Vx is the velocity of a particle moving along the xaxis as shown. If x = 2.0 m at t = 1.0 s, what is the position of the particle at t = 6.0 s?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0These are the answers they give me +2.0 m 6.0 m −1.0 m −2.0 m +1.0 m

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0find the area under the curve it'll give the total displacement till t= 1 sec , the area under the curve is =(20)*1+1/2 (42)*(21)=3 units it's given the particle was on x=2 units at t=1 so so it was on x=1 at the starting Let's find first the area of graph above x axis= 1/2 *(20)*(40)=4 units in +ve x axis direction area below the x axis = 1/2 (62)(20)=4 units so the total displacement will be 4+4=0 so it'll be at it's original position x=1 option 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks a bunch it worked

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0please could any one tell me why x=1
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