anonymous
  • anonymous
Vx is the velocity of a particle moving along the x-axis as shown. If x = 2.0 m at t = 1.0 s, what is the position of the particle at t = 6.0 s?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
here is the graph
1 Attachment
anonymous
  • anonymous
These are the answers they give me +2.0 m 6.0 m −1.0 m −2.0 m +1.0 m
ash2326
  • ash2326
find the area under the curve it'll give the total displacement till t= 1 sec , the area under the curve is =(2-0)*1+1/2 (4-2)*(2-1)=3 units it's given the particle was on x=2 units at t=1 so so it was on x=-1 at the starting Let's find first the area of graph above x axis= 1/2 *(2-0)*(4-0)=4 units in +ve x -axis direction area below the x -axis = 1/2 (6-2)(-2-0)=-4 units so the total displacement will be -4+4=0 so it'll be at it's original position x=-1 option 3

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anonymous
  • anonymous
thanks a bunch it worked
anonymous
  • anonymous
2+(5*vx)
anonymous
  • anonymous
please could any one tell me why x=-1

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