## anonymous 4 years ago when the sun directly overhead, a hawk dives toward the ground with costan velocity of 5.30 m/s at 52.5 degree below the horizontal. calculate the speed of her shado on level ground

We need to determine the horizontal component of velocity. $\cos(\theta) = {v_h \over v}$where $$\theta$$ is the angle to the horizontal, $$v_h$$ is the horizontal component of velocity, and $$v$$ is the given velocity of the hawk.