anonymous
  • anonymous
Consider The polnomial: P(x)=40x^3+116x^2-24x-36.....with one of its zeros being x1=-3. Find the remaining zeros by using synthetic division. answer choices: 1.x2,3=-1/2,4/5 2.None of these 3.x2,3=-1/4,4/5 4.x2,3=-1/2,3/5 5x2,3=-1/4,3/5 (can someone help me work this out work provided so i can understand this question more in case or future reference? plz and ty ^.^)
Mathematics
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anonymous
  • anonymous
Consider The polnomial: P(x)=40x^3+116x^2-24x-36.....with one of its zeros being x1=-3. Find the remaining zeros by using synthetic division. answer choices: 1.x2,3=-1/2,4/5 2.None of these 3.x2,3=-1/4,4/5 4.x2,3=-1/2,3/5 5x2,3=-1/4,3/5 (can someone help me work this out work provided so i can understand this question more in case or future reference? plz and ty ^.^)
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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dumbcow
  • dumbcow
x = -3 --> x+3 = 0 So you have to divide P(x) by x+3 to solve for remaining 2 zeros using synthetic division, put -3 on outside and the coefficients on inside remember to multiply then add, multiply then add ... -3| 40 116 -24 -36 -120 12 36 --------------------- 40 -4 -12 0 The resulting numbers are the coefficients of the quotient, notice the remainder is zero P(x) = (x+3)(40x^2 -4x -12) = 0 Solve the quadratic 40x^2 -4x -12 = 0 Divide equation by 4 10x^2 -x -3 = 0 Factor or use quadratic formula 10x^2 +5x -6x -3 = 0 5x(2x +1) -3(2x +1)=0 (2x+1)(5x -3) = 0 2x+1 = 0 --> x = -1/2 5x-3=0 --> x = 3/5

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