A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Consider The polnomial: P(x)=40x^3+116x^224x36.....with one of its zeros being x1=3. Find the remaining zeros by using synthetic division.
answer choices:
1.x2,3=1/2,4/5
2.None of these
3.x2,3=1/4,4/5
4.x2,3=1/2,3/5
5x2,3=1/4,3/5
(can someone help me work this out work provided so i can understand this question more in case or future reference? plz and ty ^.^)
anonymous
 5 years ago
Consider The polnomial: P(x)=40x^3+116x^224x36.....with one of its zeros being x1=3. Find the remaining zeros by using synthetic division. answer choices: 1.x2,3=1/2,4/5 2.None of these 3.x2,3=1/4,4/5 4.x2,3=1/2,3/5 5x2,3=1/4,3/5 (can someone help me work this out work provided so i can understand this question more in case or future reference? plz and ty ^.^)

This Question is Closed

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0x = 3 > x+3 = 0 So you have to divide P(x) by x+3 to solve for remaining 2 zeros using synthetic division, put 3 on outside and the coefficients on inside remember to multiply then add, multiply then add ... 3 40 116 24 36 120 12 36  40 4 12 0 The resulting numbers are the coefficients of the quotient, notice the remainder is zero P(x) = (x+3)(40x^2 4x 12) = 0 Solve the quadratic 40x^2 4x 12 = 0 Divide equation by 4 10x^2 x 3 = 0 Factor or use quadratic formula 10x^2 +5x 6x 3 = 0 5x(2x +1) 3(2x +1)=0 (2x+1)(5x 3) = 0 2x+1 = 0 > x = 1/2 5x3=0 > x = 3/5
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.