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anonymous

  • 5 years ago

1+2+3+...+49+50=

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  1. anonymous
    • 5 years ago
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    s=n(n+1)/2

  2. anonymous
    • 5 years ago
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    50.51/2=25.51

  3. anonymous
    • 5 years ago
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    \[\sum_{k=1}^{n}k=\frac{n(n+1)}{2} \implies \sum_{k=1}^{50}=\frac{50(51)}{2}=1275\]

  4. anonymous
    • 5 years ago
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    don't you think it's much much easier to be solved

  5. anonymous
    • 5 years ago
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    ya.........

  6. anonymous
    • 5 years ago
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    ....No? That is the easiest way to solve it? lol

  7. anonymous
    • 5 years ago
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    We can do this by two methods: 1.The Formula Method(malevolence has already done it) 2.The Gaussian Pairing Tool : 50+1=51,49+2=51......therefore 1+2+.......+49+50 = 51*50/2 = 1275

  8. anonymous
    • 5 years ago
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    You could just add them up but you'll get the same number...

  9. anonymous
    • 5 years ago
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    lol

  10. anonymous
    • 5 years ago
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    i mean just solve it not writing the formula

  11. anonymous
    • 5 years ago
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    dnt complicate it aron

  12. anonymous
    • 5 years ago
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    The "Gaussian Pairing Tool" is the formula...

  13. anonymous
    • 5 years ago
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    Its just generalized to n things being added...I just wanted to show you where it came from...Type it into wolfram if you just want the number.

  14. wasiqss
    • 5 years ago
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    we can also use programing :D

  15. anonymous
    • 5 years ago
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    lol

  16. anonymous
    • 5 years ago
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    no dont....

  17. wasiqss
    • 5 years ago
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    w8 lemme make it :D

  18. anonymous
    • 5 years ago
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    can u teach me about addition of harmonic mean

  19. anonymous
    • 5 years ago
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    hey let's pass it . this question doesn't worth to discuss on

  20. wasiqss
    • 5 years ago
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    tanu did that in high school bt may b i will revise on tuesday and then teach u ok

  21. anonymous
    • 5 years ago
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    it's for elementry school

  22. anonymous
    • 5 years ago
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    malevolence ur good

  23. wasiqss
    • 5 years ago
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  24. wasiqss
    • 5 years ago
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    a program that calculates sum of arithematic series with difference =1

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