Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Denebel Group TitleBest ResponseYou've already chosen the best response.0
dw:1327221848252:dw I have trouble determining which is u?
 2 years ago

Aron_West Group TitleBest ResponseYou've already chosen the best response.0
\[1/2 [e^{x} (sinxcosx)]+constant \]
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.0
Lol. I need to do IBP. which is the u?
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
u = e^x , dv = cos x
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
just so happens for this problem, either way works but in general, set u to nontrig and nonlog functions
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.0
I got stuck at this part:dw:1327222750455:dw
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.0
dw:1327222868911:dw
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
do integration by parts again with integral of e^x *sinx
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
dw:1327223148495:dw be careful of double negatives
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.0
i solved it b some diff method take ln both sides, comes out to b lny=lncosxx and it also equals to e^lncosxx=y hence now its very easy to integrate
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.0
\[e^(\ln \cos xx)\]
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.0
this is only three steps
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
how is that ^^ easy to integrate ??
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.0
I need to use IBP for the assignment :( @dumbcow: yes... but what happens to the e^(x)? do I integrate that...?
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.0
lol cox anything raised to power of e , is that u take differential of anything in power wrt to x and divide on e
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.0
\[(cosx/sinxcosx)e^(\ln cosxx)\]
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.0
like integral of e^x is differentiate what ever is in power and divide by e so it comes out to b e^x
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
repeat integration by parts u = e^x , dv = sin x du = e^x, v = cos(x) dw:1327223482801:dw
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.0
dumbcow in mine only one integration and fairly easy one
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.0
Oh, wait, there isn't a double negative right? Because dw:1327223660348:dw
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.0
Wait I am going backwards..
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
@wasiqss: it doesn't work like that when integrating if the derivative of the exponent is not a constant Example: integral e^(x^2) dx != e^(x^2)/2x "!=" means not equal
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
denebel, were you able to follow my work
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.0
Sorry, no..
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
dw:1327225190587:dw this is where i repeated integration by parts
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.0
\[let I=\int\limits_{}^{}e ^{x}\cos x, also let u=e ^{x} , du=e ^{x} , dv=\cos xdx, v=\sin x\]
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.0
\[so that I=e ^{x}\sin x+\int\limits_{}^{}e ^{x}\sin x\]
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.0
\[again let u=e ^{x},du=e ^{x}, dv=\sin x,v=\cos xdx\]
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.0
\[\therefore I=e ^{x}\sin x +[e ^{x}\cos x\int\limits_{}^{}(e ^{x}\cos xdx)\]] \[I=e ^{x}\sin x+[e ^{x}\cos x I]\]
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.0
\[2I=e ^{x}\sin xe ^{x}\cos x=e ^{x}(\sin x\cos x)\] \[I=[e ^{x}(\sin x \cos x)/2]\]
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.