A community for students.
Here's the question you clicked on:
 0 viewing
Denebel
 4 years ago
Use parts and solve for the unknown integral.
Denebel
 4 years ago
Use parts and solve for the unknown integral.

This Question is Closed

Denebel
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327221848252:dw I have trouble determining which is u?

Aron_West
 4 years ago
Best ResponseYou've already chosen the best response.0\[1/2 [e^{x} (sinxcosx)]+constant \]

Denebel
 4 years ago
Best ResponseYou've already chosen the best response.0Lol. I need to do IBP. which is the u?

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1just so happens for this problem, either way works but in general, set u to nontrig and nonlog functions

Denebel
 4 years ago
Best ResponseYou've already chosen the best response.0I got stuck at this part:dw:1327222750455:dw

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1do integration by parts again with integral of e^x *sinx

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327223148495:dw be careful of double negatives

wasiqss
 4 years ago
Best ResponseYou've already chosen the best response.0i solved it b some diff method take ln both sides, comes out to b lny=lncosxx and it also equals to e^lncosxx=y hence now its very easy to integrate

wasiqss
 4 years ago
Best ResponseYou've already chosen the best response.0this is only three steps

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1how is that ^^ easy to integrate ??

Denebel
 4 years ago
Best ResponseYou've already chosen the best response.0I need to use IBP for the assignment :( @dumbcow: yes... but what happens to the e^(x)? do I integrate that...?

wasiqss
 4 years ago
Best ResponseYou've already chosen the best response.0lol cox anything raised to power of e , is that u take differential of anything in power wrt to x and divide on e

wasiqss
 4 years ago
Best ResponseYou've already chosen the best response.0\[(cosx/sinxcosx)e^(\ln cosxx)\]

wasiqss
 4 years ago
Best ResponseYou've already chosen the best response.0like integral of e^x is differentiate what ever is in power and divide by e so it comes out to b e^x

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1repeat integration by parts u = e^x , dv = sin x du = e^x, v = cos(x) dw:1327223482801:dw

wasiqss
 4 years ago
Best ResponseYou've already chosen the best response.0dumbcow in mine only one integration and fairly easy one

Denebel
 4 years ago
Best ResponseYou've already chosen the best response.0Oh, wait, there isn't a double negative right? Because dw:1327223660348:dw

Denebel
 4 years ago
Best ResponseYou've already chosen the best response.0Wait I am going backwards..

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1@wasiqss: it doesn't work like that when integrating if the derivative of the exponent is not a constant Example: integral e^(x^2) dx != e^(x^2)/2x "!=" means not equal

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1denebel, were you able to follow my work

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327225190587:dw this is where i repeated integration by parts

mark_o.
 4 years ago
Best ResponseYou've already chosen the best response.0\[let I=\int\limits_{}^{}e ^{x}\cos x, also let u=e ^{x} , du=e ^{x} , dv=\cos xdx, v=\sin x\]

mark_o.
 4 years ago
Best ResponseYou've already chosen the best response.0\[so that I=e ^{x}\sin x+\int\limits_{}^{}e ^{x}\sin x\]

mark_o.
 4 years ago
Best ResponseYou've already chosen the best response.0\[again let u=e ^{x},du=e ^{x}, dv=\sin x,v=\cos xdx\]

mark_o.
 4 years ago
Best ResponseYou've already chosen the best response.0\[\therefore I=e ^{x}\sin x +[e ^{x}\cos x\int\limits_{}^{}(e ^{x}\cos xdx)\]] \[I=e ^{x}\sin x+[e ^{x}\cos x I]\]

mark_o.
 4 years ago
Best ResponseYou've already chosen the best response.0\[2I=e ^{x}\sin xe ^{x}\cos x=e ^{x}(\sin x\cos x)\] \[I=[e ^{x}(\sin x \cos x)/2]\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.