A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 4 years ago

2n C 0 + 2n C 1 + 2n C 2 +....................2n C n = 2^(2n-1)..is it true. if yes or no, how??

  • This Question is Closed
  1. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What is C? Some constant? It's missing from the RHS..

  2. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    combination sign..

  3. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    n choose k?

  4. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    n C r = {n!/(n-r)!r!} now, can u understand my question?

  5. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes, it's n choose k

  6. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i am not getting you...

  7. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It's the same thing, n choose k is a combination e.g. binomial coefficient

  8. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it's just another way of saying it :)

  9. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay..

  10. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No.

  11. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It is false. It should be 2^n I think.

  12. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Take n=1 then 4 c 0 + 4 c 1 = 1 + 4 = 5 but 2^(2-1) is not 5.

  13. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No it should not be 2^n

  14. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You are correct it is not 2^n. I was thinking sum k=0 to n of n c k but that expression is sum k=0 to n of 2n c k

  15. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2^(2n-1).

  16. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I was speculating what the correct formula was...I said 2^n since sum k=0 to n of n c k = 2^n is a common identity but I forgot your expression was 2n c k.

  17. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Just ignore that post :) The identity is false. Just take n=1 for a counter example.

  18. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.