A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Two swimmers Chris and Sarah starts together at the same point on the bank of a wide stream that lows with a speed v. Both move at the same speed c (where c>v) relative to the water. Chris swims downstream a distance L and thenupstream the same distance. Sarah swims so that her motion relative to the Earth is perpendicular to the banks of the stream. She swims the distance L and then back the same distance , with both swimmers returning to the starting point. a) In terms of L, c, and v find the timer interval required for Chris round trip delta t_= b) In terms L c and v find the time i
anonymous
 4 years ago
Two swimmers Chris and Sarah starts together at the same point on the bank of a wide stream that lows with a speed v. Both move at the same speed c (where c>v) relative to the water. Chris swims downstream a distance L and thenupstream the same distance. Sarah swims so that her motion relative to the Earth is perpendicular to the banks of the stream. She swims the distance L and then back the same distance , with both swimmers returning to the starting point. a) In terms of L, c, and v find the timer interval required for Chris round trip delta t_= b) In terms L c and v find the time i

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0interval required for sarahs round trip. delta t_2=.....c) explain which swimmer returns first

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Chris: swims downstream at rate (c+v) swims upstream at rate (cv) t = L/(c+v) + L/(cv) = [L(cv) +L(c+v)]/(c^2 v^2) = 2Lc/(c^2 v^2) Sarah: swims at right angle relative to bankdw:1327228231796:dw x = sqrt(c^2 v^2) t = 2L/x = 2L/ sqrt(c^2 v^2) = (2L)^2/(c^2 v^2) if c < 2L, then Chris finishes first c = 2L, they finish at same time c > 2L, then Sarah finishes first

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops i messed up at the end. For Sarah, i squared t for some reason t = 2L/sqrt(c^2 v^2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sarah finishes first 2L/sqrt(c^2v^2) < 2Lc/(c^2v^2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you so much this is really helping. I understood everything except the part where x=root c^2v^2 for sarah...how so?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its just like the airplane problem, the 2 vectors with the resultant vector make a right triangle (see drawing) the magnitude of resultant vector (speed) is root c^2 v^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh right right pythagorean theorem. I missed that part ok. Thanks!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.