anonymous
  • anonymous
Two swimmers Chris and Sarah starts together at the same point on the bank of a wide stream that lows with a speed v. Both move at the same speed c (where c>v) relative to the water. Chris swims downstream a distance L and thenupstream the same distance. Sarah swims so that her motion relative to the Earth is perpendicular to the banks of the stream. She swims the distance L and then back the same distance , with both swimmers returning to the starting point. a) In terms of L, c, and v find the timer interval required for Chris round trip delta t_= b) In terms L c and v find the time i
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
interval required for sarahs round trip. delta t_2=.....c) explain which swimmer returns first
dumbcow
  • dumbcow
Chris: swims downstream at rate (c+v) swims upstream at rate (c-v) t = L/(c+v) + L/(c-v) = [L(c-v) +L(c+v)]/(c^2 -v^2) = 2Lc/(c^2 -v^2) Sarah: swims at right angle relative to bank|dw:1327228231796:dw| x = sqrt(c^2 -v^2) t = 2L/x = 2L/ sqrt(c^2 -v^2) = (2L)^2/(c^2 -v^2) if c < 2L, then Chris finishes first c = 2L, they finish at same time c > 2L, then Sarah finishes first
dumbcow
  • dumbcow
oops i messed up at the end. For Sarah, i squared t for some reason t = 2L/sqrt(c^2 -v^2)

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dumbcow
  • dumbcow
Sarah finishes first 2L/sqrt(c^2-v^2) < 2Lc/(c^2-v^2)
anonymous
  • anonymous
Thank you so much this is really helping. I understood everything except the part where x=root c^2-v^2 for sarah...how so?
dumbcow
  • dumbcow
its just like the airplane problem, the 2 vectors with the resultant vector make a right triangle (see drawing) the magnitude of resultant vector (speed) is root c^2 -v^2
anonymous
  • anonymous
Oh right right pythagorean theorem. I missed that part ok. Thanks!

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