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anonymous
 4 years ago
Two swimmers Chris and Sarah starts together at the same point on the bank of a wide stream that lows with a speed v. Both move at the same speed c (where c>v) relative to the water. Chris swims downstream a distance L and thenupstream the same distance. Sarah swims so that her motion relative to the Earth is perpendicular to the banks of the stream. She swims the distance L and then back the same distance , with both swimmers returning to the starting point. a) In terms of L, c, and v find the timer interval required for Chris round trip delta t_= b) In terms L c and v find the time i
anonymous
 4 years ago
Two swimmers Chris and Sarah starts together at the same point on the bank of a wide stream that lows with a speed v. Both move at the same speed c (where c>v) relative to the water. Chris swims downstream a distance L and thenupstream the same distance. Sarah swims so that her motion relative to the Earth is perpendicular to the banks of the stream. She swims the distance L and then back the same distance , with both swimmers returning to the starting point. a) In terms of L, c, and v find the timer interval required for Chris round trip delta t_= b) In terms L c and v find the time i

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0interval required for sarahs round trip. delta t_2=.....c) explain which swimmer returns first

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1Chris: swims downstream at rate (c+v) swims upstream at rate (cv) t = L/(c+v) + L/(cv) = [L(cv) +L(c+v)]/(c^2 v^2) = 2Lc/(c^2 v^2) Sarah: swims at right angle relative to bankdw:1327228231796:dw x = sqrt(c^2 v^2) t = 2L/x = 2L/ sqrt(c^2 v^2) = (2L)^2/(c^2 v^2) if c < 2L, then Chris finishes first c = 2L, they finish at same time c > 2L, then Sarah finishes first

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1oops i messed up at the end. For Sarah, i squared t for some reason t = 2L/sqrt(c^2 v^2)

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1Sarah finishes first 2L/sqrt(c^2v^2) < 2Lc/(c^2v^2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you so much this is really helping. I understood everything except the part where x=root c^2v^2 for sarah...how so?

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.1its just like the airplane problem, the 2 vectors with the resultant vector make a right triangle (see drawing) the magnitude of resultant vector (speed) is root c^2 v^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh right right pythagorean theorem. I missed that part ok. Thanks!
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