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anonymous

  • 5 years ago

A river flows with a steady speed v. A student swims upstream a distance d and then back to the starting point.The student can swim at speed c in still water. a) In terms of d,v, and c what time interval is required for the round tip? [I put L/(d-v) + L/(d+v) + L/c dont know if that's correct] b) What time interval would be required if the water were still? Use any variable or symbol stated above necessary. c) Which time interval is larger: swimmng in still water, it will vary, simming with and against the current

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  1. Mertsj
    • 5 years ago
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    |dw:1327237660925:dw|

  2. Mertsj
    • 5 years ago
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    \[t=\frac{d}{c-v}+\frac{d}{c+v}\]

  3. Mertsj
    • 5 years ago
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    In still water: |dw:1327237971468:dw|

  4. Mertsj
    • 5 years ago
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    \[t=\frac{2d}{c}\]

  5. anonymous
    • 3 years ago
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    Swimming with and against the current is ALWAYS longer because of the extra time required to swim against it, the total average speed of the swimmer (swiming with+against) is slower then the swimmer just swimming in still water

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