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anonymous
 5 years ago
Solve the following equation cot x(square root of 5)cosec x=2 Find the maximum and minimum for
cos x2sinx+3 .
anonymous
 5 years ago
Solve the following equation cot x(square root of 5)cosec x=2 Find the maximum and minimum for cos x2sinx+3 .

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1cot x  sqrt5 csc x =2 (cos x  sqrt5)/sin x = 2 cos x  sqrt5 = 2sin x square both sides cos^2 2sqrt5*cos x +5 = 4sin^2 = 4(1cos^2) 5cos^2 2sqrt5*cos x +1 = 0 (sqrt5cos(x) 1)^2 = 0 sqrt5*cos x = 1 cos x = 1/sqrt5 x = cos^1 (1/sqrt5) = 63.43 degrees

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1oops, 63.43 degrees doesn't work the other possible case is 360  63.43 = 296.57 degrees this way cos still equals 1/sqrt5

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1to find max/min, differentiate and set equal to zero f'(x) = sin x 2cos x = 0 2cos x = sin x tan x = 2 x = tan^1 (2) x = 116.57 and 296.57 min = 116.57 max = 296.57
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