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anonymous
 4 years ago
Find the solution for the differential equation
(dP/dt)=(0.80.2*t)*P
When P(0)=1000,
Thanks in advance
anonymous
 4 years ago
Find the solution for the differential equation (dP/dt)=(0.80.2*t)*P When P(0)=1000, Thanks in advance

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first group or separate the variables dP/P = .8 .2t dt integrate both sides ln(P) = .8t .1t^2 +C take e raised to both sides to cancel natural log P(t) = k*e^(.8t.1t^2), where k is some constant Now apply initial conditions: P(0) = 1000 1000 = k*e^0 > k = 1000 P(t) = 1000*e^(.8t.1t^2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Fuuark, thanks a lot man :)! Can't believe I didn't get it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did u do the elimination of log?
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