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anonymous

  • 4 years ago

An iron uses 355 kJ of to press a pair of pants (which takes 4.5 minutes). The iron is plugged into a 120 volt wall outlet. How much charge passes through the iron?

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  1. anonymous
    • 4 years ago
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    hey

  2. JamesJ
    • 4 years ago
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    Power is given by \[ P = VI \] (as units of volts is Joules/Coulomb and the units of current is Coulomb/sec) Now use the information from the problem to find current \( I \). Then the amount of charge that passes through the iron is \[ Q = It \]

  3. JamesJ
    • 4 years ago
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    You also need to know that Power = (Work)/(Time), the units of which are Joules/sec, known as Watts

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