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anonymous
 4 years ago
Maximizing acceleration using only mechanical energy  In Ohanian, Ch. 8.2, problem #25, the question asks to find the point at which a bungee jumper is experiencing maximum acceleration, and what that acceleration is. Anyone know the procedure for arriving at these answers? I have the equation for SHO derived, but x'' and x are both unknowns. Haven't taken Diff Eq. yet....
anonymous
 4 years ago
Maximizing acceleration using only mechanical energy  In Ohanian, Ch. 8.2, problem #25, the question asks to find the point at which a bungee jumper is experiencing maximum acceleration, and what that acceleration is. Anyone know the procedure for arriving at these answers? I have the equation for SHO derived, but x'' and x are both unknowns. Haven't taken Diff Eq. yet....

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Maximum acceleration is where F(x) is greatest. You see from the formula: F(x) = dU/dx = 687 150x = 0, that when x becomes more negative F(x) is increasing. This is obvious, because as the cord is stretched, the force it applies becomes higher. Thus maximum acceleration is at the the bottom, i.e. at the turn, where v=0 and x=14.7m. F(x) = 687  150(14.7) = 1518N a = F(x)/m = 1518N/70kg = 22 m/s2 (2.2g)
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