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anonymous

  • 5 years ago

equation of the circle shown is...

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  1. anonymous
    • 5 years ago
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    indeterminate

  2. anonymous
    • 5 years ago
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    ishaan nice picture

  3. anonymous
    • 5 years ago
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    thanks! :-D

  4. anonymous
    • 5 years ago
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    |dw:1327246965077:dw|

  5. anonymous
    • 5 years ago
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    it's an egg! :P

  6. anonymous
    • 5 years ago
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    x^2 + (y-a)^2 = a^2 x^2 + y^2 - 2ya = 0 a is the radius.

  7. anonymous
    • 5 years ago
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    lol

  8. anonymous
    • 5 years ago
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    where radius=a. a) y^2+(x-a)^2=a^2 b)x^2=y^2+a^2 c)(x+y)^2=a^2 d)x^2+(y-a)^2=a^2 e)none of the above i was gonna say none of the above but it's d isn't it?

  9. anonymous
    • 5 years ago
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    i think you can get it now

  10. anonymous
    • 5 years ago
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    ok thx

  11. anonymous
    • 5 years ago
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    is x^2+y^2=a^2 always at the origin?

  12. anonymous
    • 5 years ago
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    yeah

  13. anonymous
    • 5 years ago
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    ok thx

  14. amistre64
    • 5 years ago
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    d does look the most promising

  15. amistre64
    • 5 years ago
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    (x-0)^2 + (y-0)^2 = a^2; is centered at (0,0)

  16. 2bornot2b
    • 5 years ago
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    I second amistre64

  17. amistre64
    • 5 years ago
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    with any luck i wont be voted off the island :)

  18. anonymous
    • 5 years ago
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    Youe answer should be \( d)x^2+(y-a)^2=a^2\)

  19. anonymous
    • 5 years ago
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    wow, that took a while

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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