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anonymous

  • 5 years ago

h(t)=cot t , itervals given, π/4,3π/4 finally got the equation written out, took me and while to figure it out, sorry. book answer is -4/pi but I have no idea how to set this up

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  1. amistre64
    • 5 years ago
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    set up for?

  2. anonymous
    • 5 years ago
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    what does it mean "the answer is \[-\frac{4}{\pi}\]? there is no question, just a definition of a function \[h(t)=\cot(t)\]

  3. anonymous
    • 5 years ago
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    average rate of change

  4. anonymous
    • 5 years ago
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    oh that is a question!

  5. anonymous
    • 5 years ago
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    sorry, duh

  6. amistre64
    • 5 years ago
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    average rate of change:\[\frac{change. in. y}{change.in.x}\]from begining to end

  7. anonymous
    • 5 years ago
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    \[\frac{h(\frac{3\pi}{4})-h(\frac{\pi}{4})}{\frac{3\pi}{4}-\frac{\pi}{4}}\]

  8. amistre64
    • 5 years ago
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    \[\frac{cot(3pi/4)-cot(pi/4)}{3pi/4-pi/4}\]

  9. amistre64
    • 5 years ago
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    latex is slowing me down lol

  10. anonymous
    • 5 years ago
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    i can do the bottom: \[\frac{3\pi}{4}-\frac{\pi}{4}=\frac{\pi}{2}\]

  11. amistre64
    • 5 years ago
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    can we factor out a cot up top?

  12. anonymous
    • 5 years ago
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    lol, right

  13. amistre64
    • 5 years ago
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    tanpi/4 = 1; flip for cot = 1 tan3pi/4 = -1; flip for cot = -1

  14. amistre64
    • 5 years ago
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    -1-1 = -2 for the top

  15. amistre64
    • 5 years ago
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    \[\frac{-2}{pi/2}=-\frac{4}{pi}\]

  16. anonymous
    • 5 years ago
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    I swear math makes me seriously think I may be retarded, I just cant understand it. Very difficult for my 30 year old brain. LOL...

  17. amistre64
    • 5 years ago
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    just wait till your my age :)

  18. anonymous
    • 5 years ago
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    I hope I catch on fairly quickly because I have to pass this course.

  19. anonymous
    • 5 years ago
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    Thank you both very much!!

  20. anonymous
    • 5 years ago
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    30!! i never met anyone so old....

  21. anonymous
    • 5 years ago
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    I know! Old as dirt! LOL, at least that is how Cal. makes me feel anyway, I should know this stuff :(

  22. anonymous
    • 4 years ago
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    Sorry to jump in after 7months on this question, but I'm having trouble understanding how you factored out the cot for the top. I'm getting stuck at \[\cot(3\pi/4)−\cot(\pi/4)\] How did you arrive at 1 and -1 for the top? I plugged it into my calculator and it came up something like 0.01something.

  23. amistre64
    • 4 years ago
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    i believe that 7 months ago that was a joke :) pi/4 radians is equivalent to 45 degrees. the tangent of an angle is the slope of the line that the radius makes with the positive x axis. the cotangent is just the inverse of the tangent. |dw:1346155666663:dw| tan(pi/4) = n/n = 1, the inverse of 1 is: 1 when we have three pi/4 s, we end up with a 135 degree angle; |dw:1346155817540:dw| as such; tan(3pi/4) = -n/n = -1, the inverse is: -1 -1 - (1) = -2

  24. anonymous
    • 4 years ago
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    Ah! Thank you so much! I got the beginning bit, and the last bit, but not the actual cot bit. My prof skipped the pre-cal review, and in retrospect I knew I should've looked it over before classes started. Thanks for going into such depth, really helps. ^_^

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