Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 3, – 25), and x intercepts at x = -8 and x = 2. (Do not include the negative sign in your answer.)
y = x2 + 6x − ___

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what ?

you know it looks like
\[a(x+8)(x-2)=a(x^2+6x-16)\] so you know the constant is -16

i said TMI because the first coordinate is an unnecessary piece of information

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