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anonymous
 5 years ago
Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 3, – 25), and x intercepts at x = 8 and x = 2. (Do not include the negative sign in your answer.)
y = x2 + 6x − ___
anonymous
 5 years ago
Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of (– 3, – 25), and x intercepts at x = 8 and x = 2. (Do not include the negative sign in your answer.) y = x2 + 6x − ___

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you know it looks like \[a(x+8)(x2)=a(x^2+6x16)\] so you know the constant is 16

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i said TMI because the first coordinate is an unnecessary piece of information

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohkay thanks and are you sure that is the correct answer ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you are asked to enter it without the minus sign, so put in "16"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the point is if the vertex was not (3,25) there would be no solution to this, so it is a rather dumb question. you are given more information that the poor quadratic can handle. you might want to mention this to your math teacher

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since the vertex is (3,25) you know it looks like \[y=a(x+3)^225\] and now all you need is one more point to find out that a = 1 in other words: the vertex and one other point would give the answer!
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