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anonymous
 4 years ago
in circular motion angular mometum is cont. or angular velocity is constant??
anonymous
 4 years ago
in circular motion angular mometum is cont. or angular velocity is constant??

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JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3In uniform circular motion, is angular momentum a constant, is that what you're asking? The answer is it depends. Angular momentum, L, is by definition \[ L = r \times p = r \times mv \] This will be constant if you're measuring angular momentum from the center of the circle of motion. But for all other points, it is not.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and angular velocity differ at every point rit

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3correct, because the vector r changes with the point from which you're measuring it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i m tired to xplain this thing to arvind he is not listening.. and even accepting !!! well thnx for help he believes u thats y i ask u too ans..

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0is angular velocity same?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but do u know its linear velocity??

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3To be explicit, suppose a body of mass m = 1 kg is moving in uniform circular motion in the xyplane about the origin at a distance R at an angular velocity \( \omega \). Then the displacement vector r(t) is given by \[ r(t) = R(\cos \omega t, \sin \omega t, 0) \] The velocity is given by differentiating, \[ v(t) = R \omega ( \sin \omega t, \cos \omega t, 0) \] The angular velocity of as measured from the origin is \[ L = r \times mv = r \times v \] \[ = R^2\omega (0, 0, \cos^2 \omega t + \sin^2 \omega t) \] \[ = R^2\omega (0,0,1) \] This is constant.

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0so angular velocity is constant??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea by thi it is concluding linear velocity is const. means angular velocity is const. if r is same

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3Provided the motion is uniform (i.e., constant angular velocity omega) _and_ we are measuring angular velocity from the origin, the center of the motion. As an exercise, calculate L if we measure r from an arbitrary point (a,b). You will see it is not a constant.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wat abu my sentence i wrote i become confuse

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3Or even an arbitrary point (a,b,c) where this is not = (0,0,0)

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3In uniform circular motion, UCM, the vector r is not a constant, nor is the vector v. What is constant is the angular speed \( \omega \).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok... got it got it thnx i think brent need ur help luk at his

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3The _magnitude_ of r and v are constant. But the vectors themselves are not constant, as written above.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3The magnitude of r, \( r = R \), a constant. The magnitude of v, \( v = R\omega \), is also a constant.

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0and w is const for UCM??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont have any more medals so that i can give u :(

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.3If \( \omega \) was not constant, then the object would not be moving around at the same rate for all \( t\). But we define UCM to to be the angular velocity \( \omega \) is constant.
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