## anonymous 4 years ago I have been having major issues trying to figure this out...can someone please try and explain to me? F(20) = 40e ^0.032(20) = ~ 75.9

1. asnaseer

What is it that is confusing you?

2. asnaseer

are you confused as to how the left hand side is equal to the right hand side?$40e ^{0.032(20)} \approx 75.9$

3. asnaseer

OK, I saw from your previous posting that you don't understand how the left hand side is equal to the right hand side.

4. asnaseer

Let me try and break it down into steps for you....

5. anonymous

I don't understand how they come up with the answer

6. asnaseer

\begin{align} 40e^{0.032(20)}&=40*e^{0.032*20}\\ &=40*e^{0.64}\\ &=40*1.8965...\\ &=75.859...\\ &\approx75.9 \end{align}hope that helps...

7. anonymous

so I ignore the f(20)?

8. asnaseer

My guess is that you were given a function of the form:$f(x)=40e^{0.032x}$and were asked to evaluate the function at $$x=20$$ so that you would then get:$f(20)=40e^{0.032(20)}$

9. anonymous

yes, now for e, I would use 2.718?

10. asnaseer

yes you have the correct approximate value for e.

11. anonymous

now when I take 0.64*2.718, I get 1.7344

12. anonymous

I just don't grasp it!

13. asnaseer

you made a mistake there. it is not 2.718*0.64 but $$2.718^{0.64}$$

14. anonymous

ohhhhhhhhhhhhhhhhhh

15. asnaseer

i.e. 2.718 to the power of 0.64

16. asnaseer

don't worry too much if you don't grasp things too quickly. as long as you keep practicing, you will slowly begin to master this subject.

17. anonymous

I still get the wrong answer

18. asnaseer

what do you get?

19. anonymous

I think I got it now

20. asnaseer

:-)

21. anonymous

thank you so much!

22. asnaseer