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anonymous
 4 years ago
does anyone understand Differential equations
anonymous
 4 years ago
does anyone understand Differential equations

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i just begun D.E. and i am totally lost. find a function, y=f(x) satisfying the given differential equation and the prescribed initial condition. dy/dx= 2x+1; y(0)=3 where do i start

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1with integration id assume

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4multiply both sides by dx .. then integrate both sides

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[y' = 2x+1\] \[\int y' = \int 2x+1\] \[y=x^2+x +C\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1plug in x=0 and y=3 to solve for C

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you do these just like seperable this is 2 sections before seperable

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0intergrals as general and particular solutions

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4forget what i said, its done the way amistre showd u

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[Y(x)=\int y'\ dx\] \[Y(x)=\int (2x+1)dx\] stuff like that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it just shows you the equation and intial condition and you have to choose what to do. So when you work it out it becomes what you are doing with the integral

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4\[\frac{dy}{dx}=2x+1\]\[dy=(2x+1)dx\]now integrate both sides\[\int\limits{dy}=\int\limits{(2x+1)dx}\]\[y=x^2+x+c\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea, just like that, thanks,

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i need help with intergals, it has been 2 yrs since i have done them. x times sq. root of x^2+9

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4let u=x^2+9 du=2x so integration becomes\[\frac{1}{2} \int\limits{ \sqrt u}du\]

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4integrate sqrt u then substitute the x back

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4I am really sorry, i have to leave now. Post a new question and someone else could help you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is \[^{?} \int\limits_{?}^{?} xe ^{x}\] u substitution or by parts integral

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1or simply recognize that your missing a 1 in front

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1by parts with that one

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1e^x + x e^x  1 e^x  = x e^x  e^x +0 

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1+C if youaint got bounds

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i missed a negative on there .... bad fingers, bad!!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[xe^{x}e^{x}\ or\ e^{x}(x+1)\]
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