A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Solve 32x + 2 − 7 = 5 for x. Show your work.
anonymous
 4 years ago
Solve 32x + 2 − 7 = 5 for x. Show your work.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0start with \[32x+2=12\] then \[2x+2=4\] then solve two equations \[2x2=4\] and \[2x+2=4\] separately, get two different solutions

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0so we have \[6x+17=5\] Add 7 on both sides \[6x+1=12 =>x+1=\frac{12}{6}=>x+1=2\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0Now we have to solve \[x+1=2 \text{ or } x+1=2\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0I think satellite made a type0 is first equation should be 2x+2=4 lol

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0i made a typeo his* not is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Distribute 3 to 2x+2. That equals 6x +6. 6x+67=5 Isolate the variable by moving all of the numbers over to one side. 6 6 +7 +7 6x=6 Divide by 6 to get x alone x=6

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0you mean x=1 which is one solution

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0there is another solution x=3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah that's what i meant! :) I'm not that great at math, so some things slip. Anyways, that's how I think you should do it, but I can't be a hundred percent sure.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.