A boy standing on a stationary lift (open from above) throws a ball upwards with the maximum initial speed he can, equal to 49 m/s. How much time does the ball take to return to his hands? If the lift starts moving up with a uniform speed of 5 m/s and the boy again throws the ball up with the maximum speed he can, how long does the ball take to return to his hands?

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A boy standing on a stationary lift (open from above) throws a ball upwards with the maximum initial speed he can, equal to 49 m/s. How much time does the ball take to return to his hands? If the lift starts moving up with a uniform speed of 5 m/s and the boy again throws the ball up with the maximum speed he can, how long does the ball take to return to his hands?

Physics
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u see i got first part
10 s
but i dont undestand y we get same answr in 2nd case

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The position of the ball at time time is \[ y(t) = 49 t - \frac{1}{2}gt^2 \] \[ = 49 t - 4.9t^2 \] \[ = 0 \] when \( t = 0, 10 \) seconds, right. Now in the second case, the speed of the ball is (49 + 5) m/s = 54 m/s, so it's position is \[ y_{ball}(t) = 54 t - 4.9t^2 \] ... but ...
the position of the boy is \[ y_{boy}(t) = 5t \] Hence the question is: for what t is \[ y_{ball}(t) = y_{boy}(t) \] Solve that equation and you'll get back \( t = 0, 10 \) seconds.
hw u got pos of boy as 5t??
because the lift is moving up at a constant velocity of 5 m/s
wow i got the old eqn
:)
right, exactly
thx
so shall i make it general
that if someone is in a lift and the lift moves with const speed then time to throw and catch the balll is same as when lift is at rest??
Yes.
k
wt if it was not const speed?
Then you won't have equality.
Frames of reference moving at a constant speed are called inertial frames. The laws of Newtonian physics work the same in all inertial frames.
u mean any system with a=0 is an inertial frame?
Yes
wow
wel james hav u seen a type of problem in which a rope is given and we can slide down that and the breaking tension is given and max a with which we can slide down??
Yes, but I'm going to go now. I'm sure gogind or jemurray or others can help you with that.
oh bye

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