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AravindG
 5 years ago
how to calculate v,and a from this graph??
AravindG
 5 years ago
how to calculate v,and a from this graph??

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AravindG
 5 years ago
Best ResponseYou've already chosen the best response.1u see i need a and v at 1.5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Put some labels on the axes :D.

AravindG
 5 years ago
Best ResponseYou've already chosen the best response.1actually i need only sign of a and v

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Like gogind said, we need labels. We have no idea how "v" or "a" relates to this sine wave.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If that is x on the yaxis, as in distance. then you would get v(t) as at derivative of x(t) with respect to t (change in distance over time is velocity) . Similarly you would get a(t) as the derivative of v(t) with respect to t or second derivative of x(t) with respect to t (change is velocity over time is acceleration). Now you have to figure out what x(t) is. It is \[\ x(t) = sin(\pi t)\] so now: \[\ v(t) = \frac{d x(t)}{dt} \]\[\ a(t)=\frac{dv(t)}{dt}=\frac{d^2x(t)}{dt^2}\] All you have to do now is differentiate.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Actually, \[\ x(t) = Asin(\pi t)\], Where A is the amplitude of the sine wave. You didn't provide the amplitude so I assumed it's 1.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1327325940478:dw always draw a tangent to the given point at the curve here at 1.5m,tangent6 is parallel to xaxis so NO ANGLE MADE WITH XAXIS now for acceleration,take any point b before the time (2 seconds is less than 1.5 seconds) then draw a tangent at b we cxan see that it makes an obtuse angle with x=axis meaning ve velocity accleration=0(velocity)/time=+ve acceleration edhe pole tangent varachu nooki angle nooki sum cheidhal answer kitum!

AravindG
 5 years ago
Best ResponseYou've already chosen the best response.1thx salini i was looking for tht answr very helpful thx thx gogind too

AravindG
 5 years ago
Best ResponseYou've already chosen the best response.1one doubt y we take v as ve wen angle is obtuse?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the basic trignometry defines tan@ of obtuse angles to be ve(2nd quadrant)
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