how to calculate v,and a from this graph??

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how to calculate v,and a from this graph??

Physics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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|dw:1327254348794:dw|
u see i need a and v at -1.5
Put some labels on the axes :D.

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actually i need only sign of a and v
Like gogind said, we need labels. We have no idea how "v" or "a" relates to this sine wave.
|dw:1327295200296:dw|
sorry for tht
If that is x on the y-axis, as in distance. then you would get v(t) as at derivative of x(t) with respect to t (change in distance over time is velocity) . Similarly you would get a(t) as the derivative of v(t) with respect to t or second derivative of x(t) with respect to t (change is velocity over time is acceleration). Now you have to figure out what x(t) is. It is \[\ x(t) = -sin(\pi t)\] so now: \[\ v(t) = \frac{d x(t)}{dt} \]\[\ a(t)=\frac{dv(t)}{dt}=\frac{d^2x(t)}{dt^2}\] All you have to do now is differentiate.
Actually, \[\ x(t) = -Asin(\pi t)\], Where A is the amplitude of the sine wave. You didn't provide the amplitude so I assumed it's 1.
|dw:1327325940478:dw| always draw a tangent to the given point at the curve here at -1.5m,tangent6 is parallel to x-axis so NO ANGLE MADE WITH X-AXIS now for acceleration,take any point b before the time (-2 seconds is less than -1.5 seconds) then draw a tangent at b we cxan see that it makes an obtuse angle with x=axis meaning -ve velocity accleration=0-(-velocity)/time=+ve acceleration edhe pole tangent varachu nooki angle nooki sum cheidhal answer kitum!
thx salini i was looking for tht answr very helpful thx thx gogind too
one doubt y we take v as -ve wen angle is obtuse?
the basic trignometry defines tan@ of obtuse angles to be -ve(2nd quadrant)

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