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anonymous

  • 4 years ago

there are 28 hours left until the final exam on calculus 1...and i havent read anything the entire semester...what can i do to pass?

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  1. amistre64
    • 4 years ago
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    take it again next term?

  2. dumbcow
    • 4 years ago
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    28 hrs left?, im guessing this was on online class

  3. anonymous
    • 4 years ago
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    if you have any old papers with answers - cram cram and cram!!

  4. anonymous
    • 4 years ago
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    nope...real life...aprox:28 hrs left tic-toc...

  5. dumbcow
    • 4 years ago
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    how did you do on the prev tests?

  6. anonymous
    • 4 years ago
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    70 and 74...on the midterms...but i didn't study anything EVER!

  7. anonymous
    • 4 years ago
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    CRAM?

  8. anonymous
    • 4 years ago
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    -ster?

  9. dumbcow
    • 4 years ago
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    not too bad considering...practice practice practice and you'll pass http://tutorial.math.lamar.edu/Classes/CalcI/CalcI.aspx this will help

  10. anonymous
    • 4 years ago
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    thanks!...i'll check it out cause the book is a bit confusing...and i cant read my notes since my letters are like hyroglyphs

  11. anonymous
    • 4 years ago
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    cram = constant hard study

  12. anonymous
    • 4 years ago
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    :S ... and where do u derive that from?

  13. anonymous
    • 4 years ago
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    how did u come up with that?

  14. anonymous
    • 4 years ago
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    cram uk slang for a session of hard study in a short time thats all

  15. anonymous
    • 4 years ago
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    let me dig on that...since all i do in my life is wait for the last day to study hard :D

  16. anonymous
    • 4 years ago
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    http://onlineslangdictionary.com/meaning-definition-of/cram

  17. anonymous
    • 4 years ago
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    yea - i used to do that a lot of the time when i was younger!

  18. anonymous
    • 4 years ago
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    first result :) lol ....it tottally describes me!!!

  19. anonymous
    • 4 years ago
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    lol

  20. anonymous
    • 4 years ago
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    how did it work for you?

  21. anonymous
    • 4 years ago
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    hatzitesla is able to study for the calculus exam at the asymptotically increasing rate of \[f(t) = \frac{t}{900-t^2},\] where t is the number of hours studied. If the total proportion of material understood after N hours is given by \[P(N) = \int\limits_{0}^{N} \frac{t}{900-t^2}dt,\] and hatzitesla only needs P(N) >= 100% = 1.0 to ace the exam, what is the minimum number of hours N that hatzitesla needs to spend studying instead of chatting on openstudy?

  22. anonymous
    • 4 years ago
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    holy...!!!man....that was some....math genius pellet....thumbs up!!!...and openstudy is actualy helpfull.(instead of fb for that matter).

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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