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anonymous
 4 years ago
Expand the Expression x>0 , y>0 , z>0
log (x^2/yz^4)
anonymous
 4 years ago
Expand the Expression x>0 , y>0 , z>0 log (x^2/yz^4)

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0log a/b = loga  logb log ab = loga + logb

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0him can you elaborate more please

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0not really, those are the basic rules for log operations. I can complicate them, but I doubt I can make them any easier ...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you giveme an example and work it out

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0ok, but its just gonna be the same thing but with numbers in there

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0log (1/2) = log(1)log(2) log(4*3) = log(4)+log(3) log(6^3) = 3 log(6)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0youll need all these operations to expand the one youve got

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the final answer would be 3log(6)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0loga (x^2/yz^4)what do i do with a

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0"a" stays the same unless your asked to change of base it

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0log (x^2/yz^4) do you see the division sign? the fraction bar? split this into its subtraction parts

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yesI understand it now! thanks

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0log (x^2/yz^4) = log (x^2)  log (yz^4) where you see the multiplication, split it into its addition parts log (x^2/yz^4) = log (x^2)  log (y)+ log(z^4) and where you see exponents, turn it into its like parts

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0log (x^2/yz^4) = 2log (x)  log (y)+ 4log(z)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0the base "a" doesnt change thruout it unless directed otherswise

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0i might have a typo in there :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0log (x^2/yz^4) = log (x^2)  (log (y)+ log(z^4)) is better since the hole of it is subtracted log (x^2/yz^4) = log (x^2)  log (y)  log(z^4) and then its the same from there
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