anonymous
  • anonymous
Expand the Expression x>0 , y>0 , z>0 log (x^2/yz^4)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
log a/b = loga - logb log ab = loga + logb
amistre64
  • amistre64
log n^r = r logn
anonymous
  • anonymous
him can you elaborate more please

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
not really, those are the basic rules for log operations. I can complicate them, but I doubt I can make them any easier ...
anonymous
  • anonymous
can you giveme an example and work it out
amistre64
  • amistre64
ok, but its just gonna be the same thing but with numbers in there
amistre64
  • amistre64
log (1/2) = log(1)-log(2) log(4*3) = log(4)+log(3) log(6^3) = 3 log(6)
amistre64
  • amistre64
youll need all these operations to expand the one youve got
anonymous
  • anonymous
so the final answer would be 3log(6)?
anonymous
  • anonymous
loga (x^2/yz^4)--what do i do with a
amistre64
  • amistre64
"a" stays the same unless your asked to change of base it
amistre64
  • amistre64
log (x^2/yz^4) do you see the division sign? the fraction bar? split this into its subtraction parts
anonymous
  • anonymous
yesI understand it now! thanks
amistre64
  • amistre64
log (x^2/yz^4) = log (x^2) - log (yz^4) where you see the multiplication, split it into its addition parts log (x^2/yz^4) = log (x^2) - log (y)+ log(z^4) and where you see exponents, turn it into its like parts
amistre64
  • amistre64
log (x^2/yz^4) = 2log (x) - log (y)+ 4log(z)
amistre64
  • amistre64
the base "a" doesnt change thruout it unless directed otherswise
amistre64
  • amistre64
i might have a typo in there :)
amistre64
  • amistre64
log (x^2/yz^4) = log (x^2) - (log (y)+ log(z^4)) is better since the hole of it is subtracted log (x^2/yz^4) = log (x^2) - log (y) - log(z^4) and then its the same from there

Looking for something else?

Not the answer you are looking for? Search for more explanations.