anonymous
  • anonymous
please show all steps and simplify 2^(logbase2 3+logbase2 5)??
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
step one: post question to openstudy.com
ash2326
  • ash2326
\(2^ { log 3+ log 5}\) log is to the base 2 log A + Log B= log AB and \[ x^{log (y)}= y\] is log is to the base x so \[2^{ log 15}\] = \( log 15\)
anonymous
  • anonymous
@ash: everything except that the last step should be = 15. Compare to: \[2^{\log_2 3 + \log_2 5} = 2^{\log_2{3}}\cdot2^{\log_2{5}}\] \[2^{\log_2{3}}\cdot2^{\log_2{5}} = 3 \cdot 5 = 15\]

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ash2326
  • ash2326
sorry i made mistake it's 15

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