pottersheep
  • pottersheep
Find a quadratic equation with the roots 3 + 4i and 3 - 4i. HELP PLEASE!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
when given roots; just reconstruct the poly with them
amistre64
  • amistre64
x=(a,b) (x-a)(x-b)=0
ash2326
  • ash2326
if we are given roots as a and b , then the equation is given as (x-a)(x-b)=0 here the roots are 3+4i and 3 -4i (x-(3+4i))(x-(3-4i)) x^2-(3+4i+3-4i)x-(9-16)=0 x^2-6x-7=0

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amistre64
  • amistre64
if anything:\[x=\frac{-b+\sqrt{b^2-4ac}}{2a}\]
amistre64
  • amistre64
3 = -b/2a -3/2 = b/a 2x^2 -3x + c = 0 is a sort of way to see it
amistre64
  • amistre64
except for I mistyped it lol
amistre64
  • amistre64
-6/1 = b/a x^2 -6x + c = 0
pottersheep
  • pottersheep
but my answers say x^2 + 6x + 25 :s
anonymous
  • anonymous
The simplest "Vieta's Formula" is x^2 - (sum)x + (product) in this case we get x^2 - 6x + 25

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